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2 years ago

What is the effective resistance of this dc circuit

Physics

1 answer:

Inessa05 [86]2 years ago

5 0

You've managed somehow to post the mirror image of the circuit diagram, including the numbers and values of the resistors. I'm curious to know how you did that.

The three resistors at the left end of the diagram are 3Ω , 2Ω , and 1Ω all in series. They behave like a single resistor of (3+2+1) = 6Ω .

That 6Ω resistor is in parallel with the 2Ω drawn vertically in the middle of the diagram. That combination acts like a single resistor of 1.5Ω in that position.

Finally, we have that 1.5Ω resistor in series with 1Ω and 4Ω . That series combination behaves like a single resistor of <em>6.5Ω</em> across the battery V.

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miv72 [106K]

Answer:

17.95025
172.3995

Explanation:

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2 years ago

You, a 70 kg person, leap from a 10 m tall building and land feet first on a trampoline. The center of the trampoline where you

Anon25 [30]

Answer:

1373.4 N/m

Explanation:

Hooke's law states that the extension of a spring and force are related by the expression, F=kx where k is spring constant, x is extension of spring and F is the applied force. Making k the subject of the formula then

$k=\frac {F}{x}$

Also, F=gm hence the above formula is modified as

$k=\frac {gm}{x}$

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3 years ago

What property of matter is momentum related to

Rudik [331]

Momentum is related to mass. In fact, it's directly proportional to mass.

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2 years ago

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The graphs show the motion of an object in both the x and y directions. Classify the motion of this object.

Natali5045456 [20]

B It is moving in one dimension

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3 years ago

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Two identical charges, 2 m apart, exert forces of magnitude 4 N on each other. The value of each charge is: 1. 9 × 105 C 2. 4.2

lesya692 [45]

Answer:

The value of each charge is 4.22 x 10⁻⁵ C

Explanation:

Given;

distance between the two identical charges, d = 2 m

the force of repulsion between these two charges, F = 4N

Apply Coulomb's law;

$F = \frac{kq_1q_2}{r^2} \\\\but \ q_1 =q_2,then \ let \ q_1 =q_2 = q\\\\F = \frac{kq^2}{r^2}\\\\q^2 = \frac{Fr^2}{k}\\\\q^2 = \frac{4*2^2}{9*10^9} \\\\q ^2 = 1.7778*10^{-9}\\\\q = \sqrt{1.7778*10^{-9}}\\\\q =4.22 *10^{-5} C\\\\q= q_1=q_2= 4.22 *10^{-5} C$

Therefore, the value of each charge is 4.22 x 10⁻⁵ C

7 0

3 years ago