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Dimas [21]
2 years ago
5

What is the effective resistance of this dc circuit

Physics
1 answer:
Inessa05 [86]2 years ago
5 0

You've managed somehow to post the mirror image of the circuit diagram, including the numbers and values of the resistors.  I'm curious to know how you did that.

The three resistors at the left end of the diagram are  3Ω ,  2Ω , and  1Ω  all in series.  They behave like a single resistor of  (3+2+1) = 6Ω .

That  6Ω  resistor is in parallel with the  2Ω  drawn vertically in the middle of the diagram.  That combination acts like a single resistor of  1.5Ω  in that position.

Finally, we have that  1.5Ω  resistor in series with  1Ω  and  4Ω  .  That series combination behaves like a single resistor of  <em>6.5Ω</em>  across the battery V.  

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miv72 [106K]

Answer:

  1. 17.95025
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Explanation:

1.

\mathrm{The\:solution\:for\:Long\:Division\:of}\:\frac{2.995}{0.16685}\:\\\mathrm{is}\:17.95025

2.

\mathrm{Multiply\:without\:the\:decimal\:points,\:then\:put\:the\:decimal\:point\:in\:the\:answer}\\\\910\times\:18945=17239950\\\\910\mathrm{\:has\:}0\mathrm{\:decimal\:places}\\0.18945\mathrm{\:has\:}5\mathrm{\:decimal\:places}\\\\\mathrm{Therefore,\:the\:answer\:has\:}5\mathrm{\:decimal\:places}\\\\=172.39950\\\\Refine\\=172.3995

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2 years ago
You, a 70 kg person, leap from a 10 m tall building and land feet first on a trampoline. The center of the trampoline where you
Anon25 [30]

Answer:

1373.4 N/m

Explanation:

Hooke's law states that the extension of a spring and force are related by the expression, F=kx where k is spring constant, x is extension of spring and F is the applied force. Making k the subject of the formula then

k=\frac {F}{x}

Also, F=gm hence the above formula is modified as

k=\frac {gm}{x}

Taking g as 9.81 m/s2 , x as 0.5 m and m as 70 kg then

k=\frac {9.81\times 70 kg}{0.5m}=1373.4 N/m

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3 years ago
What property of matter is momentum related to
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The graphs show the motion of an object in both the x and y directions. Classify the motion of this object.
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lesya692 [45]

Answer:

The value of each charge is 4.22 x 10⁻⁵ C

Explanation:

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Apply Coulomb's law;

F = \frac{kq_1q_2}{r^2} \\\\but \ q_1 =q_2,then \ let \ q_1 =q_2 = q\\\\F = \frac{kq^2}{r^2}\\\\q^2 = \frac{Fr^2}{k}\\\\q^2 = \frac{4*2^2}{9*10^9} \\\\q ^2 = 1.7778*10^{-9}\\\\q = \sqrt{1.7778*10^{-9}}\\\\q =4.22 *10^{-5} C\\\\q= q_1=q_2= 4.22 *10^{-5} C

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7 0
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