Question

The base of a parallelogram is 8 units, and the height is 5 units. A segment divides the parallelogram into two identical trapezoids. The height of each trapezoid is 5 units. Draw the parallelogram and the two trapezoids on the grid shown. Then find the area of one of the trapezoids. *The grid is a normal grid*

Answer 1

So it is a line of symmetry. 8x5=40 so the area of one is 40.
 

Answer 2

Answer:

20 sq.units

Step-by-step explanation:

Given: The base of a parallelogram is 8 units, and the height is 5 units. A segment divides the parallelogram into two identical trapezoids. The height of each trapezoid is 5 units

To Find: Area of one of the trapezoid.

Solution: Consider the file attached with solution.

In Parallelogram ABCD,

$\text{CD}$=$8\text{unit}$

 $\text{height}=5\text{unit}$

therefore,

area of parallelogram $area(\text{ABCD})=\text{base}\times\text{height}$

                                                            $8\times5$

                                   $area(\text{ABCD})$=$40\text{unit}$

Segment EF divides parallelogram in two identical trapezoid AEFD and CFEB

therefore,

$area(\text{AEFD})=area(\text{CFEB})$

also,

$area(\text{AEFD})+area(\text{CFEB})=area(\text{ABCD})$

now area of one of the trapezoid $\text{AEFD}$

$2\times area(\text{AEFD})=area(\text{ABCD})$

$area(\text{AEFD})=\frac{area(\text{ABCD})}{2}$

$area(\text{AEFD})=\frac{40}{2}=20$

The area of trapezoid is $20\text{sq.units}$