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defon
3 years ago
14

The base of a parallelogram is 8 units, and the height is 5 units. A segment divides the parallelogram into two identical trapez

oids. The height of each trapezoid is 5 units. Draw the parallelogram and the two trapezoids on the grid shown. Then find the area of one of the trapezoids. *The grid is a normal grid*

Mathematics
2 answers:
Zigmanuir [339]3 years ago
6 0
So it is a line of symmetry. 8x5=40 so the area of one is 40.
 
Goryan [66]3 years ago
4 0

Answer:

20 sq.units

Step-by-step explanation:

Given: The base of a parallelogram is 8 units, and the height is 5 units. A segment divides the parallelogram into two identical trapezoids. The height of each trapezoid is 5 units

To Find: Area of one of the trapezoid.

Solution: Consider the file attached with solution.

In Parallelogram ABCD,

\text{CD}=8\text{unit}

 \text{height}=5\text{unit}

therefore,

area of parallelogram area(\text{ABCD})=\text{base}\times\text{height}

                                                            8\times5

                                   area(\text{ABCD})=40\text{unit}

Segment EF divides parallelogram in two identical trapezoid AEFD and CFEB

therefore,

area(\text{AEFD})=area(\text{CFEB})

also,

area(\text{AEFD})+area(\text{CFEB})=area(\text{ABCD})

now area of one of the trapezoid \text{AEFD}

2\times area(\text{AEFD})=area(\text{ABCD})

area(\text{AEFD})=\frac{area(\text{ABCD})}{2}

area(\text{AEFD})=\frac{40}{2}=20

The area of trapezoid is 20\text{sq.units}

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