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3 years ago

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A stadium has a shape of a circle with a diameter 105 meters. Lamp posts will be planted on the circumference of the stadium, wi

th a distance of 6 meters between two lamp posts. How many lamp posts needed?

1 answer:

grandymaker [24]3 years ago

3 0

Circumference = 105*pi

about 329.8672286269

and that divided by 6 is 54.9778714378, which is about 55

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The average number of points you scored in the first 9 basketball games of the season was 23. What do you need in the 10th game

Vlada [557]

Answer:

B. 10n-207

Step-by-step explanation:

Given,

The average number of points of 9 games = 23,

∵ Sum of observations = their average × number of observations

So, the total points for 9 games = 9 × 23 = 207,

Now, if the average of 10 games is n,

Then the total points for 10 games = 10n,

Hence, the number of points earned in 10th game = the total points for 10 games - the total points for 9 games

= 10n - 207

i.e. OPTION B is correct.

3 0

3 years ago

The leg of the isosceles triangle is two less than three times the length of its base. If the perimeter of the triangle is 45 m,

choli [55]

Answer:

19 m

Step-by-step explanation:

base=x

leg=3x-2

3x-2+3x-2+x=45

7x-4=45

7x=49

x=7

leg=3x+2=3(7)-2=19

7 0

3 years ago

An office building loses a third of its heat between sundown and midnight and an additional half of the original amount of heat

Mekhanik [1.2K]

Answer:

$\dfrac{1}{16}$

Step-by-step explanation:

Proportion of Heat Loss Between sundown and midnight $=\dfrac{1}{3}$

Proportion of Heat Loss between midnight and 4 AM $=\dfrac{1}{2}$

Proportion of Total Heat Already Lost $=\dfrac{1}{3}+\dfrac{1}{2} =\dfrac{5}{6}$

Proportion of Remaining Heat $=1-\dfrac{5}{6}=\dfrac{1}{6}$

Between 4 AM and 5 AM, five-eighths of the remaining heat is lost.

Proportion of Heat Loss between 4 AM and 5 AM= $\dfrac{5}{8}$ X \dfrac{1}{6} = \dfrac{5}{48}$

Therefore, Proportion of Remaining Heat Left $=\dfrac{1}{6}- \dfrac{5}{48}=\dfrac{1}{16}$

We therefore say that:

$\dfrac{1}{16}$ of the total heat loss occurs between 5 AM and sunrise.$

6 0

3 years ago

The local library had a sale to get rid of the books that were slightly damaged it’s on paper back books for two dollars and har

kondor19780726 [428]

Answer:

The Local Library sold <u>31</u> hardcover books.

Step-by-step explanation:

Let number of paper back books be 'x'.

Let number of hardcover books be 'y'.

Given:

Total number of books sold = 89

Now Total number of books sold is equal to sum of number of paper back books and number of hardcover books.

framing in equation form we get;

$x+y=89 \ \ \ \ \ equation \ 1$

Now Given:

Cost of each paper back books = $2

Cost of each hardcover books = $5

Total Amount raised by library = $271

Now We know that Total Amount raised by library is equal to Cost of each paper back books multiplied by number of paper back books plus Cost of each hardcover books multiplied number of hardcover books.

framing in equation form we get;

$2x+5y=271 \ \ \ \ equation \ 2$

Now Multiplying equation 1 by 2 we get;

$2(x+y)=89\times2\\\\2x+2y = 178 \ \ \ \ equation \ 3$

Now Subtracting equation 3 from equation 2 we get;

$(2x+5y)-(2x+2y)=271-178\\\\2x+5y-2x-2y=93\\\\3y = 93\\\\y=\frac{93}{3}=31$

Substituting the value of y in equation 1 we get;

$x+y =89\\\\x+31=89\\\\x =89-31 = 58$

Hence The Local Library sold 58 paper back books and <u>31</u> hardcover books.

8 0

3 years ago

11cm by 6 cm rectangle

puteri [66]

Answer:

Question unclear.

If the question was about the perimeter of the rectangle, it is calculated as:

= (Length * 2) + (Height * 2)

= (11 * 2) + (6 * 2)

= 22 + 12

= 34 cm

If the question was bout Area, the area is:

= Length * width

= 11 * 6

= 66 cm²

8 0

3 years ago