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Natalka [10]
3 years ago
14

The electric power consumed by a circuit with one light bulb is 24 W. The voltage of the battery is 3 V. What is the current in

the circuit?
Physics
1 answer:
IceJOKER [234]3 years ago
5 0

Answer:

8 ampere

Explanation:

P= V x I

so

I = P/V

I= 24 /3

I = 8 A

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What is meant by infinite slew rate
Dennis_Churaev [7]
Am infinite slew rate means that the changes in the output voltage occur immensely when the input voltage changes.
Slew rate is measurement of the response of an operational amplifier. For an ideal operational amplifier, time delay is negligible. Hence it has an infinite slew rate.
In simpler terms it means that it can provide output voltage simultaneously with the input voltage changes.

Hope this helps :)
3 0
3 years ago
Wha is the frequency of a wave having a period equal to 18 seconds?
Rainbow [258]

Answer:

5.5 × 10-2 hertz

Explanation:

The time taken by a wave crest to travel a distance equal to the length of wave is known as wave period.

= 0.055 per second          (1 cycle per second = 1 Hertz)

Thus, we can conclude that the frequency of the wave is 5.5 X 10^{-2} hertz.

Hopes this helps, love <3

5 0
3 years ago
An electron is accelerated through a potential difference of 2.8 kV and directed into a region between two parallel plates separ
RoseWind [281]

Answer:

B=1.89*10^{-4} T

Explanation:

First we have to calculate the electric force on the electron, and then we have to take into account that this force is equal to the force generated by the magnetic field.

The formula is

F=q_eE\\\\E=\frac{V}{d}

q: charge of the electron = 1.6*10^{-19}C

V: potential

d: separation between plates

E=\frac{100V}{17*10^{-3}m}=5882.35N/C

F=(1.6*10^{-19}C)(5882.35N/C)=9.4*10^{-16}N

This force must equal the Lorentz's force

F_E=F_B\\\\F_B=qvB\\\\B=\frac{F_B}{q_ev}

But before we have to calculate the speed of the electron by using  (me=9.1*10^{-31}kg)

E_e=\frac{1}{2}m_ev^2=q_eV\\\\v=\sqrt{\frac{2q_eV}{m_e}}=\sqrt{\frac{2(1.6*10^{-19}C)(2.8*10^3V)}{9.1*10^{-31}kg}}\\\\v=3.13*10^7\frac{m}{s}

Hence, we have

B=\frac{9.4*10^{-16}N}{(1.6*10^{-19}C)(3.1*10^{7})\frac{m}{s}}=1.89*10^{-4}T

hope this helps!!

8 0
3 years ago
Read 2 more answers
The velocity of a car is 108 km h-1 what is the velocity in units of ms -1
Anarel [89]

\frac{108 \times 10^3 }{60 \times 60}  \\  \frac{108 \times 10^3 }{3600} \\  = 30 { ms }^{ - 1}
3 0
3 years ago
Solve for the missing values using the inverse square
Ipatiy [6.2K]

Answer:

                                     1             2               3          4            5

 New force ( N )           1.25      0.4166      48      175         150

Explanation:

We know that ,

Force ( f ) ∝ distance ( d )

1 )

initial distance =40 m

initial force = 5 N

F ∝ d

F = k d     ( k = proportionality constant )

5 = k * 40

k = (1/8)

new distance = 10 m

new force = ( 1/8 ) * 10 = 1.25 N

2)

d = 72 m

F = 2.5 N

k = 2.5/72

new distance = 12 m

new force = ( 2.5/72 ) * 12 = 0.4166 N

3)

d = 12 m

F = 8 N

k = 2/3

new distance = 72 m

new force = ( 2/3 ) *72 =  48 N

4 )

d = 6 m

F = 25 N

k = 25/6

new distance = 42 m

new force = ( 25/6)*42  = 175 N

5)

d = 10 m

F = 50 N

k = 5

new distance = 30 m

new force = 5 * 30 = 150 N

 

3 0
3 years ago
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