Answer:
h f = W + KE
Input energy equals work function plus KE of emitted electron
W = 6.63E-34 * 2.5E15 - 6.3 * 1.6E-19
W = 6.63 * 2.5 * 10^-19 - 10.1 * E-19 ev (1ev = 1.6E-19 J)
W = (16.6 - 10.1)E-19 = 6.5E-19 J
h f = 6.5E-19 J for electrons to be emitted with zero KE
f = 6.5E-19 / 6.63E-34 = .98E-15 / sec = 9.8E-14 / sec (threshold)
Answer:
The bullet that is fired will spend longer in the air, hitting the ground after the dropped bullet.
Explanation:
Using the equation: x
= x
0 +
v
t
If we neglect the effects of air resistance, the horizontal motion is a constant velocity.
The horizontal displacement = (velocity X cosθ)
So, the fired bullet has to travel horizontally before falling which takes a longer time compared to a bullet dropped where it is, height = 1/2 gt^2
gravity, g = 9.8 m/s2.
Answer:
A) m = F/a = 91.7/9.81 = 9.35 kg
B) m = F/a = 59.2/9.81 = 6.03 kg
C) m = F/a = 33.4/9.81 = 3.40 kg
D) m = F/a = 9.65/9.81 = 0.984 kg
Explanation:
Answer:
86.6 lbs
Explanation:
Let the force is X.
Resultant force, R = 100 lbs
Other force is Y. Angle between resultant force and force X is 30°.
According to the diagram
X = 86.6 lbs
Other force Y
Y = 50 lbs
