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allochka39001 [22]
3 years ago
5

A metal wire is in thermal contact with two heat reservoirs at both of its ends. Reservoir 1 is at a temperature of 781 K, and r

eservoir 2 is at a temperature of 335 K. Compute the total change in entropy arising from the conduction of 1477 J of heat through the wire. Please give your answer in units of J/K.
Physics
1 answer:
andreev551 [17]3 years ago
6 0

Answer:2.517 J/K

Explanation:

Given

Reservoir 1 Temperature T_1=781 K

Reservoir 2 Temperature T_2=335 K

Let Q is the amount of heat Flows i.e. Q=1477 J

thus change in Entropy is given by \frac{\sum Q}{T}

\Delta S=\frac{\sum Q}{T}=-\frac{Q}{T_1}+\frac{Q}{T_2}

\Delta S=\frac{\sum Q}{T}=-\frac{1477}{781}+\frac{1477}{335}

\Delta S=\frac{\sum Q}{T}=-1.891+4.4089

\Delta S=\frac{\sum Q}{T}=2.517 J/K                              

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The nearest plant (A) receives 4 times more radiation from the farthest plant

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Therefore, the linear charge density is 5.19 X 10⁻⁶ C/m

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