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olga2289 [7]
3 years ago
13

ANSWERRRRRRRRRRRRRRR PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEREEEEEEE

Chemistry
1 answer:
MAXImum [283]3 years ago
4 0

Answer:

The 2nd choice correctly models a longitudinal wave. (I attached a pic)

Explanation:

It starts off compression and next is rarefaction. It then continues to go back and forth between the two.

Hope that helps!!

:D


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2.
katovenus [111]

Answer:

A. 6atm

Explanation:

Using pressure law equation:

P1/T1 = P2/T2

Where;

P1 = initial pressure (atm)

T1 = initial temperature (K)

P2 = final pressure (atm)

T2 = final temperature (K)

According to this question;

P1 = 3 atm

P2 = ?

T1 = 120K

T2 = 240K

Using P1/T1 = P2/T2

3/120 = P2/240

Cross multiply

240 × 3 = P2 × 120

720 = 120P2

P2 = 720/120

P2 = 6atm

4 0
3 years ago
PLEASE HELP ME (JOULES)
Svetllana [295]

Answer:

The answer is not 9.9 i used that and got it wrong

Explanation:

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2 years ago
Balance :FeCl3 + __Ca(OH)2 → ___ Fe(OH)3 + __ CaCl2
ArbitrLikvidat [17]
Your answer is 2:3:2:3
7 0
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A 35 MGD surface Water treatement plant proposes to to use alum Coagulation for turbidity reduction using 44 mg/ L alum. the raw
CaHeK987 [17]
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3 years ago
What is the emperical formula of a compound containing 40.1% carbon and 6.6% hydrogen​
levacccp [35]

Answer:

CH₂

Explanation:

Given parameters:

Percentage composition:

          Carbon  = 40.1%

          Hydrogen  = 6.6%

Unknown:

Empirical formula of the compound  = ?

Solution:

The empirical formula of a substance is its simplest formula.

 Elements                             Carbon                             Hydrogen

Percentage

Composition                           40.1                                     6.6

Molecular mass                        12                                         1

Number of moles                  40.1/12                                  6.6/1

                                                3.342                                    6.6

Divide through by

the smallest                         3.342/3.342                           6.6/3.342

                                                      1                                        2

So the empirical formula of the compound is CH₂

5 0
3 years ago
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