Question

How much CaCO3 would have to be decomposed to produce 247 g of CaO

Answer 1

441 g CaCO₃ would have to be decomposed to produce 247 g of CaO

Further explanation

Reaction

Decomposition of CaCO₃

CaCO₃ ⇒ CaO + CO₂

mass CaO = 247 g

mol of CaO(MW=56 g/mol) :

$\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{247}{56}\\\\mol=4.41$

From equation, mol ratio CaCO₃ : CaO = 1 : 1, so mol CaO :

$\tt \dfrac{1}{1}\times 4.41=4.41$

mass CaCO₃(MW=100 g/mol) :

$\tt mass=mol\times MW\\\\mass=4.41\times 100\\\\mass=441~g$