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3 years ago

What mass of iron (III) nitrate will be in 129.8ml of a 0.3556 molar aq iron (III) nitrate solution?

Chemistry

1 answer:

Anvisha [2.4K]3 years ago

6 0

Answer: The mass of iron (III) nitrate is 11.16 g/mol

Explanation:

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 0.3556 M

Molar mass of Iron (III) nitrate = 241.86 g/mol

Volume of solution = 129.8 mL

Putting values in above equation, we get:

$0.3556M=\frac{\text{Mass of iron (III) nitrate}\times 1000}{241.86 g/mol\times 129.8}\\\\\text{Mass of iron (III) nitrate}=11.16g$

Hence, the mass of iron (III) nitrate is 11.16 g/mol

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