Question

The quadratic function f(x) = –x2 – 6x – 8 is graphed. What are the solutions of the quadratic equation 0 = –x2 – 6x – 8?

Answer 1

-x^2-6x-8=0

-x^2-2x-4x-8=0

-x(x+2)-4(x+2)=0

(-x-4)(x+2)=0

-(x+4)(x+2)=0

x=-4, -2 so the two solutions are the points (-4, 0), (-2, 0)

Answer 2

Answer:

Step-by-step explanation:

Hi there, every time we pick a function and instead of f(x) we place a 0. We've just turned it into an equation.

So that's the case.

$0=-x^{2} -6x-8\\ x^{2} +6x+8=0$

As a=1, then the solution may also be found through another method. Which two numbers and their product is 8? And the same two number added gives us 6?

$P(x)=4*2=8\\ S(x)=4+2=6$

As their opposite numbers to 4 and 2 so the Solution Set is

S={-4,-2}

We could find the solution through the Quadratic Formula as well

$\frac{6+\sqrt{36-4(-1)(-8)}}{2*(-1)}\\\frac{6-2}{-2}=-2 ,\frac{6+2}{-2}=-4$

S={-4,-2}