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Over [174]
3 years ago
14

You spend 10 minutes playing video games. You then spend 1 hour doing homework. Write the ratio of the amount of time spent play

ing video games to the amount of time spent doing homework as a fraction in simplest form.
"Please answer this question!"
Mathematics
2 answers:
djyliett [7]3 years ago
7 0

Answer:

The ratio would be 10:60 or 10/60.

Step-by-step explanation:

I hope it helps :)

Ainat [17]3 years ago
5 0

Answer:

its 1/6

Step-by-step explanation:

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What percent of the fruit in the breakfast buffet are apples
Afina-wow [57]

Answer:

75%

Step-by-step explanation:

there is 3x+y because of the oranges and apples, there's 4 different fruits so we can say it's 4z. Then 100/4 which is 25, 25 is for oranges and 75 is for apples

3 0
3 years ago
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Due to recent energy crisis in California, rolling blackouts were necessary and more might be necessary in the future. Assume th
Illusion [34]

Answer:

The probability of the temperature exceeding 65 degrees Fahreneit but not needing a rolling blackout is 0.4- Hence, there is a 40% chance.

Step-by-step explanation:

Lets call F the event 'the temperature will exceed 85 degrees Fahrenheit' and B the event 'a blackout will be needed'.

We want P(F ∩ B^c), note that if F happens, there could be 2 disjoint possible events: B or B^c, hence

P(F) = P(F ∩ B) + P(F ∩ B^c)

Hence

P(F ∩ B^c) = P(F) - P(F ∩ B) = 0.6 - 0.2 = 0.4

7 0
3 years ago
Read 2 more answers
Solve for x:
Fantom [35]

2x + 6 + 3x + 12 = 33

5x + 18 = 33

5x = 33-18

5x = 15

therefore x=3

3 0
3 years ago
Expected Value (50 points)
garri49 [273]

Let W be the random variable representing the winnings you get for playing the game. Then

W=\begin{cases}10-1=9&\text{if the dice sum is odd}\\5-1=4&\text{if the dice sum is 4 or 8}\\50-1=49&\text{if the dice sum is 2 or 12}\\-1&\text{otherwise}\end{cases}

First thing to do is determine the probability of each of the above events. You roll two dice, which offers 6 * 6 = 36 possible outcomes. You find the probability of the above events by dividing the number of ways those events can occur by 36.

  • The sum is odd if one die is even and the other is odd. This can happen 2 * 3 * 3 = 18 ways. (3 ways to roll even with the first die, 3 ways to roll odd for the die, then multiply by 2 to count odd/even rolls)
  • The sum is 4 if you roll (1, 3), (2, 2), or (3, 1), and the sum is 8 if you roll (2, 6), (3, 5), (4, 4), (5, 3), or (6, 2). 8 ways.
  • The sum is 2 if you roll (1, 1), and the sum is 12 if you roll (6, 6). 2 ways.
  • There are 36 total possible rolls, from which you subtract the 18 that yield a sum that is odd and the other 10 listed above, leaving 8 ways to win nothing.

So the probability mass function for this game is

P(W=w)=\begin{cases}\frac12&\text{for }w=9\\\frac29&\text{for }w=4\text{ or }w=-1\\\frac1{18}&\text{for }w=49\\0&\text{otherwise}\end{cases}

The expected value of playing the game is then

E[W]=\displaystyle\sum_ww\,P(W=w)=\frac92+\frac89-\frac29+\frac{49}{18}=\frac{71}9

or about $7.89.

7 0
3 years ago
Roger question here keep it simple and clear
mixer [17]

Answer:

13

Step-by-step explanation:

6 0
3 years ago
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