Question

Sid is packing crushed ice into a cone-shaped cThe cone has a height of 5 in. Its base has a diameter of 4 in. What is thevolume of the cone?20 320 in80 380r in 3

Answer 1

$The\ volume\ of\ the\ cone:V=\dfrac{1}{3}\pi r^2H\\\\H=5\ in\\2r=4\ in\to r=2\ in\\\\subtitute\\\\V=\dfrac{1}{3}\pi\cdot2^2\cdot5=\dfrac{1}{3}\pi\cdot4\cdot5=\dfrac{20}{3}\pi\ (in^3)\\\\Answer:\boxed{V=\dfrac{20}{3}\pi\ in^3}$

Answer 2

Answer:

(A) The volume of the cone is $\frac{20}{3}{\pi}inches^3$.

Step-by-step explanation:

It is given that the cone has a height of 5 inches and the base has the diameter equals to 4 inches, therefore the radius of the cone can be obtained as:

$Radius=\frac{Diameter}{2}$

$Radius=\frac{4}{2}=2$inches

And height=5inches

Now, the volume of the cone is obtained as:

$v=\frac{1}{3}{\pi}r^2h$

Substituting the given values, we get

$v=\frac{1}{3}{\pi}(2)^2(5)$

$v=\frac{20}{3}{\pi}inches^3$

Thus, the volume of the cone is $\frac{20}{3}{\pi}inches^3$.

Hence, option A is correct.