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sashaice [31]
2 years ago
15

The mean per capita consumption of milk per year is 144 liters with a variance of 484. If a sample of 183 people is randomly sel

ected, what is the probability that the sample mean would be less than 146.58 liters? Round your answer to four decimal places.
Mathematics
1 answer:
trapecia [35]2 years ago
8 0

Answer:

12144

Step-by-step explanation11213123:

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What is the probability of the occurrence of a number that is odd or less than 5
yaroslaw [1]

Answer:

Hence the probability of getting a number less than 5 is 2/3.

Step-by-step explanation:

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1 year ago
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Solve 247 divided by 10(^2) . and 247x10 (^2)<br><br> what's different about the two answers?
guajiro [1.7K]
247 divided by 10^2 is 2.47 and 247 times 10^2 is 24,700

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3 years ago
Complete the graduated commission problem: You earn 20%
guajiro [1.7K]

Answer: I'll give you both the percentage and dollar amount. 75% = $144

Step-by-step explanation: first, I added up all the percentages to total 75%. then I took the total sales, and divided that by .75 (75% in decimal form), so:

1940 x .75 = 1455

1940 - 1455 = 144

3 0
2 years ago
An account earns simple interest. (a) Find the interest earned. (b) Find the
Debora [2.8K]

Answer:

#a. $80

#b. $1680

Step-by-step explanation:

We are given;

  • Amount invested (principal) is $1600
  • Rate of interest is 5%
  • Time = 1 year

We are required to determine the amount of simple interest earned and the amount or balance in the account after 1 year.

#a. Interest earned

To calculate simple interest we use the formula;

I = (PRT) ÷ 100

Where, P is the principal, R is the rate, T is the time and I is the simple interest.

Therefore;

I = (1600 × 5 × 1) ÷ 100

 = $80

Therefore, simple interest earned is $80

#b. Balance of the account (Amount accrued)

We are going to use the formula;

A = P + I , where A is the amount accrued, P is the principal and I is the simple interest earned.

Therefore;

Account balance = $1600 + $80

                            = $1680

Thus, the account balance after 1 year will be $1680

8 0
2 years ago
A average amount of money on deposit in a savings account is $7500. Suppose a random sample of 49 accounts shows the average in
Valentin [98]

Answer:  

z=-3.79

p_v =2*P(z  

Step-by-step explanation:  

1) Data given and notation  

\bar X=6850 represent the mean average amount of money on deposit in savings account for the sample  

\sigma=1200 represent the population standard deviation for the sample  

n=49 sample size  

\mu_o =7500 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean for the amount of money on deposit in savings account differs from 7500, the system of hypothesis would be:  

Null hypothesis:\mu =7500  

Alternative hypothesis:\mu \neq 7500  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{6850-7500}{\frac{1200}{\sqrt{49}}}=-3.79  

4)P-value  

Since is a two-sided test the p value would be:  

p_v =2*P(z  

5) Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the average amount of money deposit in savings account its significantly different from 7500 tons at 1% of signficance.  

7 0
3 years ago
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