Answer:
The correct answer is - XDXd and XD Y
Explanation:
Sex-linked disorders are the disorders that are expressed only when there is two copy of the mutated allele or have not masked by the dominant allele of the gene. In DMD, the dominant allele is XD and the mutated allele is Xd. To express it there are the following genotype possible-
in women XdXd, and in men XdY, so these two genotypes are not possible for the parents in this case. If a mutated allele is present with the dominant allele it will be considered as carrier women but diseased will not be found in them.
So the correct genotype would be
mother: XDXd ( a carrier woman)
father : XDY (normal man)
The monomers of DNA are called Nucleotides. They are made up of a 5-carbon sugar(deoxyribose), a phosphate group and a nitrogenous base bound to the sugar. Adenine makes two bonds with Thyamine whereas Cytosine makes three bonds with Guanine.
Most blood flows across to the left atrium through a shunt called the foramen ovale. then from the <span>left atrium, </span>blood<span> moves down into the lower chamber of the </span>heart. <span>It is then pumped into the first part of the large artery coming from the </span><span>heart</span>
<span>when the breaking down of acetylcholine is not performed, then symptoms similar to those of poisoning with acetylcholinesterase inhibitors would occur. This would be highly hazardous to the human system as severe poisoning as we all know is very lethal. Even a fetus would not develop with this.</span>
