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Rzqust [24]
3 years ago
5

Suppose that f is differentiable on [-5,8]. If f has a local maximum at 2, what does f'(2) equal?

Mathematics
1 answer:
Firlakuza [10]3 years ago
5 0
If the maximum is at 2, that means f'(2) = 0 (tan Ф =0)
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What is the name of the special type of quadrilateral shown here?
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I believe you're looking for rhombus.
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Olivia is making model cars to go on shelves in her room. The number of wheels she uses is a function of how many cars she makes
Luba_88 [7]

Answer:

Domain = 1 to 7

Range = 4 to 28

Step-by-step explanation:

Given that:

Number of wheels used is a function of number of cars manufactured.

Number of wheels present = 28

1 car uses 4 wheels

2 cars use 8 wheels.

3 car uses 12 wheels

and so on.

Let the function be of the form:

y =f(x)

Domain of the function is the value of x that can be given as valid input to the function.

Range of the function is the value of y that can be output of the function.

Let x be the number of cars manufactured.

Then value of y is nothing but x times 4.

y=4x

We are given that maximum value of y can be 28.

28 = 4x\\\Rightarrow x =7

Therefore, maximum value of input can be 7.

Minimum number of wheels can be 4 to make a minimum of 1 car.

Therefore domain is 4 to 28 and range is 1 to 7.

3 0
3 years ago
How to figure square feet of walk way
artcher [175]

Answer:

To calculate what you need, multiply the walkway's width and length to find the square footage.

Step-by-step explanation:

To calculate what you need, multiply the walkway's width and length to find the square footage; for example a 4-foot-wide, 50-foot-long walkway covers 200 square feet. Next, factor in the thickness: 4 inches converts to 0.33 feet; multiply this by the square footage to find the cubic feet: 200 x 0.33 = 66 cubic feet.

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7 1/2 x 3/4 = 45/8 =
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Step-by-step explanation:

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Lex was chatting with his friends thomas and mike. He was wondering how much it will cost him to take a taxi from his house to w
UNO [17]

Answer:

$28.3

Step-by-step explanation:

x=rate for 1km

y=initial fee

Mike: $35 for 15km -> 35 = 15x + y

Thomas: $24.50 for 10km -> 24.50 = 10x + y

Using those two equations we see the following:

Mike paid $10.5 more for 5 more km. The initial fee remains unchanged, so we can calculate the rate for 1km, which is 10.5/5=2.1.

35 = 15x + y

24.50 = 10x + y

10.5 = 5x

2.1=x

Using that value with one of the original equations we can calculate the initial fee.

35 = 15x + y

35 = 15*2.1 + y

35 = 31.5 + y

3.5 = y

Mike paid 15*2.1=31.5 ($2.1 for every km) plus the initial fee, his total was $35.

We subtract the 31.5 from the 35(total) and get the initial fee, which is $3.5.

<u>Let's see what Lex will pay:</u>

Km travelled times 2.1 (the rate for 1km) plus 3.5 (the initial fee).

12*2.1 + 3.5 = 28.3

Lex will pay $28.3 for the same taxi company to travel 12 km.

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