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2 years ago

Select the correct answer. Which statement is true about the graphed cubic function?

Mathematics

2 answers:

sineoko [7]2 years ago

5 0

Step-by-step explanation:

The cubic function passes the x-axis only once,

so there is 1 distinct real zeroes and 2 complex zeroes.

devlian [24]2 years ago

3 0

<h3>The correct answer is (B)</h3><h3></h3><h3><em>The function has one distinct real zero and two complex zeros.</em></h3>

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Given:

oksian1 [2.3K]

Answer:

9 units

Step-by-step explanation:

By the midsegment theorem,

$AB=\dfrac{KN+LM}{2}$

Since the ratio $LM:KN=1:5,$ then $LM=x,\ KN=5x$ and

$18=\dfrac{x+5x}{2}\\ \\18=\dfrac{6x}{2}\\ \\18=3x\\ \\x=6\\ \\LM=6\ units\\ \\KN=30\ units$

Draw two heights LE and MF. Quadrilateral ELMF is a rectangle, then EF = LM = 6 units.

Trapezoid KLMN is isosceles trapezoid (KL = MN), then KE = FN and

$KE=FN=\dfrac{KN-EF}{2}=\dfrac{30-6}{2}=12\ units$

Consider right triangle KLE. By the Pythagorean theorem,

$KL^2=LE^2+KE^2\\ \\15^2=LE^2+12^2\\ \\LE^2=15^2-12^2\\ \\LE^2=225-144=81\\ \\LE=9\ units$

3 0

2 years ago

Help soon eeeeeeeeeeeeeeeeeee

igomit [66]

3/9 because it is the same as 1/3 or 2/6.

6 0

2 years ago

Read 2 more answers

Solve 80% of x = 100 or 0.8x = 100

suter [353]

Answer:

125

Step-by-step explanation:

divide both sides of the equation by 0.8

0.8÷0.8=0.8÷100

any expression divided by 1 is itself

x=100÷0.8

divide the numbers

100÷0.8=125

125 is your answer

7 0

3 years ago

The comprehensive strength of concrete is normally distributed with μ = 2500 psi and σ = 50 psi. Find the probability that a ran

VARVARA [1.3K]

Answer:

The probability that the diameter falls in the interval from 2499 psi to 2510 psi is 0.00798.

Step-by-step explanation:

Let's define the random variable, $X =$ "Comprehensive strength of concrete". We have information that $X$ is normally distributed with a mean of 2500 psi and a standard deviation of 50 psi (or a variance of 2500 psi). In other words, $X \sim N(2500, 2500)$ .

We want to know the probability of the mean of X or $\bar{X}$ that falls in the interval $[2499;2510]$ . From inference theory we know that :

$\bar{X} \sim N(2500, \frac{2500}{5}) \Rightarrow \bar{X} \sim N(2500,500)$

Now we can find the probability as follows:

$P(2499 \leq \bar{X} \leq 2510) \Rightarrow P(\frac{2499 - 2500}{500} \leq \frac{\bar{X} - 2500}{500} \leq \frac{2499 - 2500}{500} ) \Rightarrow\\\Rightarrow P(-0.002 \leq \frac{\bar{X} - 2500}{500} \leq 0.02 ) \Rightarrow P(-0.002 \leq Z \leq 0.02 )$