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soldier1979 [14.2K]
3 years ago
5

Using the given information, give the vertex form equation for each parabola.

Mathematics
1 answer:
ollegr [7]3 years ago
3 0

Answer:

Step-by-step explanation:

If you plot this point and the directrix on a coordinate plane, you can see that the directrix is 1/4 of a unit below the vertex.  Since, by nature, a parabola opens in the direction opposite the directrix and "hugs" the focus, this is a positive x-squared parabola (meaning it opens upwards).  The formula for this type of a parabola is, in vertex form,

4p(y-k)=(x-h)^2

where p is distance (in units) between the vertex and the directrix and h and k are the coordinates of the vertex.  For us, p = .25, h = 7, and k = -6.  Filling in our formula:

4(.25)(y+6)=(x-7)^2

Simplify the left side to

1(y+6)=(x-7)^2 which simplifies, in its entirety, to

(x-7)^2-6=y

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Answer:

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Step-by-step explanation:

Given:

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Assume, Ti be the time between ( i-1 )st and the ith failures. Then, the T_{i} are independent with \mathrm{T}_{\mathrm{i}} being exponential with rate \frac{(101-i)}{200} .

Therefore,

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b)

The variance is given by, \mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]

\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

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