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juin [17]
2 years ago
10

A car dealership is comparing the sales of two employees. The equation that represents Kevin’s sales is S = 60n-5, where n repre

sents the number of years of employment. Dylan’s sales are displayed in the table below:
Years of Employment (n):
2
6
10
Number of Cars Sold (S)
104
324
544

(n) (S)
2 104
6 324
10 544

Compare the statement below to compare the employees’ rate of change.

greater than, 55, 60, -5, -116, 220, less than, 104, equal to

Kevin’s rate of change is _______. Dylan’s because Kevin sells_______ cars per year employed and Dylan sells ________ cars per year employed.
Mathematics
2 answers:
BARSIC [14]2 years ago
6 0

Answer:

I been trying to look for that answer for so long but can we help each other at least

umka21 [38]2 years ago
4 0

Answer:

Step-by-step explanation:

We have  Kevin's sales equation is

S=60n-5

Step 1

Find out Dylan's sales equation

Find the slope

We need two points

We take

(2,104) And (6,324)

m=(324-104)/(6-2)

m=\frac{220}{4} \\m=55

Find the equation in slope intercept form

s=mn+b

We have

m=55

point (2,104)

Substitute and solve for b

104=55(2)+b\\

b=104-110\\b=-6\\

So

S=55n-6\\

Therefore

Kevin's rate of change is 60

Dylan's rate of change is 55

Compare

Kevin's rate of change is greater than Dylan's rate of change because Kevin's sell 60 cars per year and Dylan's sells 55 cars per year.

PLEASE MARK ME AS BRAINLIEST

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xxMikexx [17]

Answer:

a) 5+13k  where k is integer

b) 20+13k where k is integer

c)12+13k where k is integer

Step-by-step explanation:

(a)

8x \equiv 1 (mod 13) \text{ means } 8x-1=13k.

8x-1=13k

Subtract 13k on both sides:

8x-13k-1=0

Add 1 on both sides:

8x-13k=1

I'm going to use Euclidean Algorithm.

13=8(1)+5

8=5(1)+3

5=3(1)+2

3=2(1)+1

Now backwards through the equations:

3-2=1

3-(5-3)=1

3-5+3=1

(8-5)-5+(8-5)=1

2(8)-3(5)=1

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5(8)-3(13)=1

So compare this to:

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We see that x is 5 while k is 3.

Anyways 5 is a solution or 5+13k is a solution where k is an integer.

b)

8x \equiv 4 (mod 13)

8x-4=13k

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Add 4 on both sides:

8x-13k=4

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If we multiply both sides by 4 we get:

8(20)-13(12)=4

So x=20 and 20+13k is also a solution where k is an integer.

c)

[tex]99x \equiv 5 (mod 13)[/tex

99x-5=13k

Subtract 13k on both sides:

99x-13k-5=0

Add 5 on both sides:

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Using Euclidean Algorithm:

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Go back through the equations:

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8(13)-99=5

99(-1)+8(13)=5

Compare this to 99x-13k=5 and see that x=-1 or -1+13=12 or 12+13k is a solution where k is an integer.

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