I believe it to be 1 over 3 as 1 as the numerator and 3 as the denominator
The equations used to find the measure of each angle in degrees is x + y = 90 and x = 6y - 1
The two complementary angles are 77 degrees and 13 degrees
<em><u>Solution:</u></em>
Given that two angles are complementary angles
Complementary angles are two angles whose sum is 90 degrees
Let one of the angle be "x" and the other angle be "y"
Therefore,
x + y = 90 ------ eqn 1
Also given that,
One angle is one less than six times the measure of another
one angle = six times the other angle - 1
x = 6y - 1 ------ eqn 2
Substitute eqn 2 in eqn 1
6y - 1 + y = 90
Thus the above equation is used to find the measure of each angle in degrees
Solve the above equation
6y + y - 1 = 90
7y - 1 = 90
7y = 91
y = 13
Substitute y = 13 in eqn 2
x = 6(13) - 1
x = 78 - 1
x = 77
Thus the two complementary angles are 77 degrees and 13 degrees
Answer:
d. 15
Step-by-step explanation:
Putting the values in the shift 2 function
X1 + X2 ≥ 15
where x1= 13, and x2=2
13+12≥ 15
15≥ 15
At least 15 workers must be assigned to the shift 2.
The LP model questions require that the constraints are satisfied.
The constraint for the shift 2 is that the number of workers must be equal or greater than 15
This can be solved using other constraint functions e.g
Putting X4= 0 in
X1 + X4 ≥ 12
gives
X1 ≥ 12
Now Putting the value X1 ≥ 12 in shift 2 constraint
X1 + X2 ≥ 15
12+ 2≥ 15
14 ≥ 15
this does not satisfy the condition so this is wrong.
Now from
X2 + X3 ≥ 16
Putting X3= 14
X2 + 14 ≥ 16
gives
X2 ≥ 2
Putting these in the shift 2
X1 + X2 ≥ 15
13+2 ≥ 15
15 ≥ 15
Which gives the same result as above.
Answer:
s = 6 cm
Step-by-step explanation:
the area (A) of a square is calculated as
A = s² ( s is the side length )
given A = 36 , then
s² = 36 ( take square root of both sides )
s = 
= 6
