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Molodets [167]
3 years ago
5

2 5------ 5 - 3 --- 5

Mathematics
1 answer:
scoundrel [369]3 years ago
7 0
What is the question or the problem
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Please help me with questions 6
loris [4]
Since A = bh
and A = 198 and b = 18?
h = A/b
= 198/18
= 11
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3 years ago
Find the measure of angle r
guapka [62]
What is the the x’s value?
5 0
3 years ago
A television was originally priced at $598.00. The price was reduced by 6%. What is the new price of the television?
aksik [14]
Hello.

To find the answer of this question, you need to find 6% of 598. 
6 / 100 = 0.06. 0.06 x 598 = 35.88. So now all you have to do is subtract 35.88 from 598. 598 - 35.88 = 562.12.

So the new price of the television is 562.12.

Have a great day! :)
8 0
3 years ago
If a, b, c, and d are coplanar lines and a is parallel to b, b is perpendicular to c, and c is parallel to d, then which stateme
Andreas93 [3]
D must be perpendicular to a because d is parallel to c. c is perpendicular to b. b is parallel to a.
4 0
3 years ago
Read 2 more answers
Which expression is equivalent to sqrt128x^5y^6/2x^7y^5 ? Assume x 0 and y > 0.
kolbaska11 [484]

<u>Answer:</u>

\frac{8\sqrt{y} }{x}

<u>Step-by-step explanation:</u>

We are given the following expression and we are to simplify it:

\sqrt {\frac {128x^5y^6} {2x^7y^5} }

To make it easier to solve, we can also write this expression as:

\sqrt {\frac{128}{2} * \frac {x^5} {x^7} * \frac {y^6} {y^5}}

Now we will cancel out the like terms to get:

\sqrt {64*\frac{1} {x^2}*y }

Taking the square root of the terms to get:

8*\frac {1}{x} .\sqrt{y}

\frac{8\sqrt{y} }{x}

4 0
3 years ago
Read 2 more answers
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