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vovikov84 [41]
3 years ago
6

Solve the variablev + 5 > 9 ​

Mathematics
2 answers:
Aloiza [94]3 years ago
5 0

Answer:

v > 4 is simplified expression.

Step-by-step explanation:

Given that:

v + 5 > 9 ​

This expression says that when 5 is added to a variable v it will be greater than 9 So we will simplify it to get the value for variable v:

Subtracting 5 from both sides:

v + 5 - 5 > 9 ​- 5

v > 4

This is the simplified expression for given question.

i hope it will help you!

d1i1m1o1n [39]3 years ago
4 0

Answer:V>4

Step-by-step explanation:

v+5>9

v>9-5

v>4

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Step-by-step explanation:

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Solve: 2cos(x)-square root 3=0 for 0 less than x less than 2 pi
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Answer:

The general solution of   cos x = cos(\frac{\pi }{6})   is  

                                                x = 2nπ±\frac{\pi }{6}

The general solution values  

                                 x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

Step-by-step explanation:

Explanation:-

Given equation is  

                              2cosx-\sqrt{3} =0  for 0

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Dividing '2' on both sides, we get

                             cos x =\frac{\sqrt{3} }{2}

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<em>General solution of cos θ = cos ∝ is θ = 2nπ±∝</em>

<em>Now The general solution of   </em>cos x = cos(\frac{\pi }{6})<em>   is  </em>

<em>                                                 x = 2nπ±</em>\frac{\pi }{6}<em></em>

put n=0

x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

Put n=1  

x = 2\pi +\frac{\pi }{6} = \frac{13\pi }{6}

x = 2\pi -\frac{\pi }{6} = \frac{11\pi }{6}

put n=2

x = 4\pi +\frac{\pi }{6} = \frac{25\pi }{6}

x = 4\pi -\frac{\pi }{6} = \frac{23\pi }{6}

And so on

But given 0 < x< 2π

The general solution values  

                                 x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

                               

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