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Norma-Jean [14]
4 years ago
6

Trim the exam the equation below and said that the equation has exactly one solution -8(x - 4) + 2x = -4(x - 8) - 2x which expla

ins whether Trina is correct:
a.) Trina is correct because the two sides of the equation are equivalent
b.) Trina is correct because the two sides of the equation are not equivalent
c.) Trina is not correct because the two sides of the equation are equivalent
d.) Trina is not correct because the two sides of the equation are not equivalent
I'm super confused on this can somebody help me​
Mathematics
1 answer:
vivado [14]4 years ago
4 0

The answer is C Trina is not correct because the two sides of the equation are equivalent

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Neeeddddd HELP LOOKONG FOR ANSWERS!!
kaheart [24]

Answer:

a.) 13 students

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Step-by-step explanation:

a.) In the given equation of y=4x+13, "x" represents how many years have gone by since the club had started. The number "13" in this equation represents the y-intercept, or the value of "y" when x = 0. Therefore, when "x" is 0 years, there were 13 students in the clubs, meaning that the original group that started the club contained 13 students.

b.) Since the question asks how many members that the club will have after their tenth year and you already know that "x" in the equation y=4x+13 represents the number of years since the club started, all you have to do is plug 10 in for "x" in the equation; so, the equation will now look like this: y=4(10)+13. Keeping PEMDAS in mind, you first multiply 4 and 10 to get 40, and then you add 13 to get an answer of 53 members after year 10.

7 0
3 years ago
7,,,,,,,,,,,,,,,,,,,,please help
Goryan [66]

Answer:

1

Step-by-step explanation:

The given expression is

\frac{2^{\frac{11}{2} }\times 2^{-7}\times 2^{-5}}{2^3\times 2^{\frac{1}{2} }\times 2^{-10}}

Recall and use

a^m\times a^n=a^{m+n}

\frac{2^{\frac{11}{2} -7-5}}{ 2^{3+\frac{1}{2} -10}}

\frac{2^{-\frac{13}{2}}}{ 2^{-\frac{13}{2}}}

Same bases are dividing, so we write one base and subtract the exponent.

2^{-\frac{13}{2}+\frac{13}{2}}

2^0=1

8 0
3 years ago
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