Consider the charge for parking one car for t hours.
If t is more than 1, then the function is y=3+2(t-1), because 3 $ are payed for the first hour, then for t-1 of the left hours, we pay 2 $.
If t is one, then the rule y=3+2(t-1) still calculates the charge of 3 $, because substituting t with one in the formula yields 3.
75% is 75/100 or 0.75.
For whatever number of hours t, the charge for the first car is 3+2(t-1) $, and whatever that expression is, the price for the second car and third car will be
0.75 times 3+2(t-1). Thus, the charge for the 3 cars is given by:
3+2(t-1)+0.75[3+2(t-1)]+0.75[3+2(t-1)]=3+2(t-1)+<span>0.75 × 2[3 + 2(t − 1)].
Thus, the function which total parking charge of parking 3 cars for t hours is:
</span><span>f(t) = (3 + 2(t − 1)) + 0.75 × 2(3 + 2(t − 1))
Answer: C</span>
<span>so quarters to nickels would be 4:20. simplified is 1:5</span>
Answer:
I'm sorry but what is the question?
Step-by-step explanation:
Answer:
probably of a head= 1/2
probably of a multiple of 3 (either 3 or 6)= 2ways*1/6 as 1/6 is the prob of any one side
Step-by-step explanation:
Answer:
It costs $154.88 to build the fences.
Step-by-step explanation:
Perimeter of square = 
We are given that A garden is in the shape of a square with a perimeter of 56 feet.
So,
Side =
So, Side of square park = 14 feet
One fence is around the perimeter of the garden, whereas the second fence is 2 feet from the first fence on the outside.
Outer length = 14+2+2=18 feet
So, Perimeter of outer fence = 
Cost of fencing 1 foot = $1.21
Cost of fencing 56 feet =
Cost of fencing 72 feet = 
Total cost = 67.76+87.12=154.88
Hence It costs $154.88 to build the fences.
