Answer:
9 (approximately)
Step-by-step explanation:
Approximate difference
= pH of basic solution - pH of acidic solution
= 11.2 - 2.4
= 8.8
= 9 (approximately)
Answer:
Absolute zero is the lowest possible temperature where nothing could be colder and no heat energy remains in a substance. Absolute zero is the point at which the fundamental particles of nature have minimal vibrational motion, retaining only quantum mechanical, zero-point energy-induced particle motion. hope this helps you
In a class of 24 kids, for every 1 boy there are 4 girls
Answer:
$148.21
Step-by-step explanation:
A suitable financial calculator, web site, or spreadsheet can figure this for you. Or you can use the formula given in your reference material (text or web site).
Answer:

Step-by-step explanation:
see the attached figure with letters to better understand the problem
step 1
In the right triangle ACD
Find the length side AC
Applying the Pythagorean Theorem

substitute the given values



simplify

step 2
In the right triangle ACD
Find the cosine of angle CAD

substitute the given values

----> equation A
step 3
In the right triangle ABC
Find the cosine of angle BAC

substitute the given values
----> equation B
step 4
Find the value of x
In this problem
----> is the same angle
so
equate equation A and equation B
solve for x
Multiply in cross


step 5
Find the length of BC
In the right triangle BCD
Applying the Pythagorean Theorem

substitute the given values



simplify
