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3 years ago

Energy derived from hot rocks and fluids beneath the earth’s surface is _____.

Physics

2 answers:

yan [13]3 years ago

7 0

Geothermal?
..................

dmitriy555 [2]3 years ago

6 0

Answer:

Geothermal

Explanation:

Geothermal energy is the energy derived from the Earth's crust. There is continuous generation of heat by the Earth's core. This heat is generated by the radioactive decay of the core from when the Earth formed. This heat can be used to make steam and generate electricity. Majority of the geothermal activities can be seen near the tectonic plate boundaries.

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Describe how kinetic and potential energy change as a diver climbs up to a diving board and then dives into the water below.

Dima020 [189]

A diver having mass m climbs up the diving board.
We know that Gravitational potential energy is given as PEG=mgΔh

What changes is his Gravitational potential energy due to change of height Δh with reference to the ground/water level.
While standing on the diving board his velocity is zero. As such kinetic energy is also zero.

Once he jumps off the springboard we see he gets additional energy from the springboard and falls down under action of gravity g. Due to decrease of height above the ground level Gravitational potential energy decreases and gets converted in to his kinetic energy. 1/2mv2.

While in air he encounters air resistance. Some of his energy is spent in overcoming this resistance. Gets converted in to kinetic and thermal energy of surrounding air and his body.

Once diver reaches the water, we see water splashing and hear noise of splash. Thereafter the diver comes to rest. Now his potential energy becomes zero. And converted kinetic energy has been converted in to kinetic energy, heat energy and sound energy of water.

As such energy transformation equation looks like

Gravitational PE+Elastic PE of springboard→Kinetic energy of air and water+Sound energy of splash+thermal energy

8 0

3 years ago

Read 2 more answers

A 15-turn circular wire loop with a radius of 3.0 cm is initially in a uniform magnetic field with a strength of 0.5 T. The fiel

miskamm [114]

Answer:

0.212V

Explanation:

The induced emf in circular loop is $\epsilon=-d\frac{\phi_B}{dt}=-NA\frac{dB}{dt}$

N = Number of loops = 15

A = Cross sectional Area = $\pi$ $0.03^{2}$ = 0.0009 $\pi$

dB = change in magnetic Field = 0-0.5 = -0.5

dt = time taken = 0.1sec

$\epsilon=-15*0.0009\pi *\frac{-0.5}{0.1}$ = 0.212V

8 0

4 years ago

To measure the potential drop across a resistor, a voltmeter is connected in ____ with the resistor.

slava [35]

A voltmeter is connected in PARALLEL with the resistor.

5 0

3 years ago

When a current flows through a metal wire, the moving charges are _______________ A. both protons and electrons. B. only electro

vladimir2022 [97]

Answer:

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3 years ago

A small rubber wheel is used to drive a large pottery wheel. The two wheels are mounted so that their circular edges touch. The

Goshia [24]

Answer:

$0.629\ \text{rad/s}^2$ counterclockwise

$9.98\ \text{s}$

Explanation:

$r_1$ = Small drive wheel radius = 2.2 cm

$\alpha_1$ = Angular acceleration of the small drive wheel = $8\ \text{rad/s}^2$

$r_2$ = Radius of pottery wheel = 28 cm

$\alpha_2$ = Angular acceleration of pottery wheel

As the linear acceleration of the system is conserved we have

$r_1\alpha_1=r_2\alpha_2\\\Rightarrow \alpha_2=\dfrac{r_1\alpha_1}{r_2}\\\Rightarrow \alpha_2=\dfrac{2.2\times 8}{28}\\\Rightarrow \alpha_2=0.629\ \text{rad/s}^2$

The angular acceleration of the pottery wheel is $0.629\ \text{rad/s}^2$ .

The rubber drive wheel is rotating in clockwise direction so the pottery wheel will rotate counterclockwise.

$\omega_i$ = Initial angular velocity = 0

$\omega_f$ = Final angular velocity = $60\ \text{rpm}\times \dfrac{2\pi}{60}=6.28\ \text{rad/s}$

t = Time taken

From the kinematic equations of linear motion we have

$\omega_f=\omega_i+\alpha_2t\\\Rightarrow t=\dfrac{\omega_f-\omega_i}{\alpha_2}\\\Rightarrow t=\dfrac{6.28-0}{0.629}\\\Rightarrow t=9.98\ \text{s}$

The time it takes the pottery wheel to reach the required speed is $9.98\ \text{s}$

4 0

3 years ago