A yellow ball with a mass of 2 kg is rolling across the floor at 3 m/s. A red ball with a mass of 3 kg is rolling across the sam
2 answers:
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Answer:
The maximum electric field strength is 0.0144 V/m.
Explanation:
Given that,
Electric potential created in the heart, V = 3.6 mV
Distance, d= 0.25 m
Frequency of the the electromagnetic wave, f = 1 Hz
We need to find the maximum electric field strength created. We know that the electric potential is given by :
E is the maximum electric field strength
So, the maximum electric field strength is 0.0144 V/m. Hence, this is the required solution.
By using Ohm's law, we can calculate the resistance of the wire. Ohm's law states that:
where V is the potential difference across the conductor, I is the current and R the resistance. Rearranging the equation, we get
Now we can use the following equation to calculate the length of the wire:
(1)
where
is the resistivity of the material
L is the length of the conductor
A is its cross-sectional area
In this problem, we have a wire of copper, with resistivity
. The radius of the wire is half the diameter:
And the cross-sectional area is
So now we can rearrange eq.(1) to calculate the length of the wire:
where V is the potential difference across the conductor, I is the current and R the resistance. Rearranging the equation, we get
Now we can use the following equation to calculate the length of the wire:
where
L is the length of the conductor
A is its cross-sectional area
In this problem, we have a wire of copper, with resistivity
And the cross-sectional area is
So now we can rearrange eq.(1) to calculate the length of the wire: