consider a sample of gas in a container on a comfortable spring day. the Celsius temperature suddenly doubles, and you transfer
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Answer:
It is 3 m/s² downward.
Explanation:
The mass of an object, m = 30 kg
Upward force, F = 200 N
Downward force, F' = -300 N
We need to find the magnitude and direction of its acceleration.
Net force = F+F'
= 200+(-300)
= -100 N
We know that,
Force, F = ma, a is acceleration of the object
Hence, the acceleration is -3 m/s² and it is acting in the downward direction.
Explanation:
The given data is as follows.
Mass, m = 75 g
Velocity, v = 600 m/s
As no external force is acting on the system in the horizontal line of motion. So, the equation will be as follows.
where, = mass of the projectile
= mass of block
v = velocity after the impact
Now, putting the given values into the above formula as follows.
=
v = 0.898 m/s
Now, equation for energy is as follows.
E =
=
= 13500 J
Now, energy after the impact will be as follows.
E' =
= 20.19 J
Therefore, energy lost will be calculated as follows.
= E E'
= (13500 - 20) J
= 13480 J
And, n =
=
= 99.85
= 99.9%
Thus, we can conclude that percentage n of the original system energy E is 99.9%.