1. Let's call the number of carter school: "x" and "y" the number of alternative school. Then, you have that:
- T<span>he number of charter schools is 4 less than twice the number of alternative schools.
</span> - T<span>here are 48 charter schools in the country.
2. So, you have:
x=2y-4 (i)
x=48 (ii)
3. Then, when you substitute x=48 into the equation (i), you obtain:
</span>
x=2y-4
<span> 48=2y-4
4. Now, you must clear "y, as below:
48+4=2y
2y=52
y=52/2
y=26
</span><span>
How many alternative schools are in the county?
</span><span>
The answer is: There are 26 alternative schools.</span>
The answer is 1,296, that's how many bacteria's there will be
This is a combination problem. The approach to this is by using the nCr method, where n is the number of total objects and r is the number of success. For example, if you want to get 3 red out of the total 4, then that would be 4C3. That means,
4C3 = 4!/3!(4 - 3)! = 4 ways
If you want to get 2 green out of the total 6, then that would be 6C2. That means,
6C2 = 6!/2!(6-2)! = 15 ways
Therefore, there are a total of 4+15 = <em>19 ways</em>.
Answer:
The difference of 6 times x subtracted from 8 is equal to the sum of 4 added to Twice x
