Step-by-step explanation:
hope it helps
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Answer:
The correct options are
(b)y²-5y=750
(c)750-y(y-5)=0
(e)(y+25)(y-30)=0
Step-by-step explanation:
Given that,
The area of rectangular room is 750 square feet.
Let the length of the rectangular room be y feet.
Since the width of the rectangular 5 less than the length of the room.
Then the width of the given rectangular room is (y-5) feet.
We know the area of a rectangular plot is = Length×width.
The area of the rectangular room is = y(y-5) square feet
According to problem,
y(y-5) =750.........(1)
⇒y²-5y=750 .......(2)
⇒y²-5y-750=0
⇒y²-30y+25y-750=0
⇒y(y-30)+25(y-30)=0
⇒(y-30)(y+25)=0 ......(3)
⇒y-30=0 or, y+25=0
⇒y= 30, -25
The length of a rectangle can't negative.
So, x=30.
We can rewrite the equation (1) in form of
(i)
y(y-5) =750
⇒750= y(y-5)
⇒750-y(y-5)=0.......(4)
(ii)
y(y-5) =750
⇒y(y-5) -750=0.......(5)
The correct options are
(b)y²-5y=750
(c)750-y(y-5)=0
(e)(y+25)(y-30)=0
Tan =opposite/adjacent
opposite = y
adjacent = 15
tan = 26.5
rearrange the fomula to make:
opposite = tan × 15 (or tan26.5* 15)
y = 7.47 or rounded to 7.5ft
Answer:
Graph both inequalities and see if the point lies in the overlapping shaded region.
Step-by-step explanation:
Answer: C
Step-by-step explanation:
This describes an expotential function
At t = 0, P = 70
Therefore, C = 70
P = 70 e^kt
Solve for k by plugging in (4,360)
k = 0.4094
plug in t(7 hours)
70 e^(0.4094*7)
The answer roughly equals C