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2 years ago

Which one is correct for this question need help please

Mathematics

1 answer:

emmainna [20.7K]2 years ago

5 0

Answer:

A is correct, 7 units. Hope this helps! :)

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sixteen dictionaries weigh 11.52 pounds all together. each dictionary has the same weight in pounds,how much does one dictionary

iogann1982 [59]

Answer:

1.92 Pounds per dictionary

Step-by-step explanation:

Since 6 dictionaries weigh 11.52 pounds, and each of the dictionaries weigh the same, this is a simple division problem.

11.52/6=1.92

3 0

2 years ago

Can somebody please clearly (and correctly) explain how to successfully work out this question?

STatiana [176]

Answer:

Step-by-step explanation:

To calculate the number of tiles needed

divide 4m by 0.2m for row of tiles ⇒ 20 tiles per row

divide 3m by 0.2m for column of tiles ⇒ 15 tiles per column

number of tiles = 20 × 15 = 300

number of packs = 300 ÷ 10 = 30

cost = 30 × £34.99 = £1049.70

Since she has £1000 to spend and £1049.70 > £1000

She does not have enough to cover the wall

6 0

2 years ago

For each rectangle below, write a linear equation that represents the area y of the rectangle. Solve this system of two linear e

Hatshy [7]

(5,24)

The two areas are the same.

To find the area, we multiply the side lengths. Y=area

Rectangle 1: side lengths 4 and (x+1)

y=4(x+1)= 4x+4

Rectangle 2: side lengths 3 and (2x-2)

y=3(2x-2)= 6x-6

Since the two areas are same, we can conclude that

4x+4=6x-6

Now, simplify.

-2x=-10, x=5

Since x is 5, we can plug it into the equations to find y.

Option 1 with rectangle 1: y=4(5)+4, y=24

Option 2 with rectangle 2: y=6(5)-5, y=24

I graphed the linear equation on desmos.

5 0

2 years ago

Y=-x^2+2x+10 y=x+2 Substitution Please show your work Need ASAP

erik [133]

Answer:

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

Step-by-step explanation:

we have

$y=-x^{2} +2x+10$ ----> equation A

$y=x+2$ ----> equation B

Solve the system by substitution

substitute equation B in equation A

$x+2=-x^{2} +2x+10$

solve for x

$-x^{2} +2x+10-x-2=0$

$-x^{2} +x+8=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2} +x+8=0$

$a=-1\\b=1\\c=8$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}$

$x=\frac{-1\pm\sqrt{33}} {-2}$

$x=\frac{-1+\sqrt{33}} {-2}$ -----> $x=\frac{1-\sqrt{33}} {2}$

$x=\frac{-1-\sqrt{33}} {-2}$ -----> $x=\frac{1+\sqrt{33}} {2}$

Find the values of y

For $x=\frac{1-\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1-\sqrt{33}} {2}+2$ ----> $y=\frac{5-\sqrt{33}} {2}$

For $x=\frac{1+\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1+\sqrt{33}} {2}+2$ ----> $y=\frac{5+\sqrt{33}} {2}$

therefore

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

5 0

2 years ago

Can someone identify this

Tresset [83]

Answer:

no entindendol ingels

Step-by-step explanation:

8 0

1 year ago

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