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3 years ago

3/4(x-12) =12 solve for x

Mathematics

2 answers:

oksian1 [2.3K]3 years ago

7 0

Answer:

Step-by-step explanation:

$\frac{3}{4}( x - 12) = 12$

Multiply through by 4 to eliminate the fraction

That's

$4 \times \frac{3}{4} (x - 12) = 12 \times 4 \\ 3(x - 12) = 48$

Expand the terms in the bracket

$3x - 36 = 48$

Add 36 to both sides of the equation

That's

$3x + 36 - 36 = 48 + 36 \\ 3x = 84$

Divide both sides by 3

$\frac{3x}{3} = \frac{84}{ 3} \\$

We have the final answer as

Hope this helps you

Varvara68 [4.7K]3 years ago

5 0

Answer:

x=28

Step-by-step explanation:

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Simplify the expression. 68 – 18 ÷ 3 • 6 Please help

MAXImum [283]

Remember PEMDAS (Parenthesis, Exponents, Multiplication, Divison, Addition and Subtraction)

Also note that Multiplication and Division needs to be done left to right and the same goes for Addition and Subtraction.

So in your problem, the first operation we need to do is division.

68 - (18/3) x 6
68 - 6 x 6

Now we do multiplication
68 - 6 x 6
68 - 36

Finally we do subtraction because that's the only operation we have left to do
68 - 36 = 32

So your answer should be 32.

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4 years ago

How many persons are in the line? Ashley is in the line to buy a ticket. There are twice as many people in front of Ashley as th

Klio2033 [76]

Answer:

I am pretty sure there are 10 people in line.

Since Ashley is the seventh person in line, we can deduce that there are 6 people in front of her.

Since the amount of people in front of her is "twice as many people as there are behind her," we can divide the value of the people in front of her in half to get the value of people behind her.

6/2 is 3, so there are 3 people behind Ashley.

Now, lets add the amount of people in front of Ashley to the amount of people behind her. 3 + 6 = 9, and since Ashley is also in the line, we should add 1 to the sum.

9 + 1 = 10, so there are 10 people in the line.

4 0

3 years ago

A manufacturer is interested in the output voltage of a power supply used in a PC. Output voltage is assumed to be normally dist

Luda [366]

The missing values in the question are shown in bold forms below.

A manufacturer is interested in the output voltage of a power supply used in a PC. Output voltage is assumed to be normally distributed, with standard deviation of 0.25 V, and the manufacturer wished to test $\mathbf{ H_o : \mu = 10 V \ against \ H_1 : \mu \neq 10V}$ , using n = 10 units. Statistical Tables and Charts

(a) The critical region is $\mathbf{\overline X < 9.83}$ or $\mathbf{\overline X < 10.17}$ . Find the value of $\mathbf{\alpha }$

Answer:

∝ = 0.032 (to 3 decimal place)

Step-by-step explanation:

From the given information:

$P(\overline X < 9.83 ) + P( X> 10.17) = \bigg (1- P \bigg ( \dfrac{X - \mu}{\dfrac{\sigma}{\sqrt{n}}} \bigg )< Z< \bigg ( \dfrac{X - \mu}{\dfrac{\sigma}{\sqrt{n}}} \bigg ) \bigg )$

$P(\overline X < 9.83 ) + P( X> 10.17) = \bigg (1- P \bigg ( \dfrac{9.83 - 10}{\dfrac{0.25}{\sqrt{10}}} \bigg )< Z< \bigg ( \dfrac{10.17- 10}{\dfrac{0.25}{\sqrt{10}}} \bigg ) \bigg )$

$P(\overline X < 9.83 ) + P( X> 10.17) = \bigg (1- P \bigg ( \dfrac{-0.17}{\dfrac{0.25}{\sqrt{10}}} \bigg )< Z< \bigg ( \dfrac{0.17}{\dfrac{0.25}{\sqrt{10}}} \bigg ) \bigg )$