I believe the answer is 1/6
I hope this helps!
Real is scaling down to the drawing, right? ...because she’d begin by measuring the real thing.
So that’s 4 ft to 8 inches, but that doesn’t make sense. They both have to be in the same measurement... either feet or inches. So 1 ft.= 12 in. So to change feet into inches, multiply 4x12= 48inches (In 4 feet) so 48 to 8 or48/8 which reduces to 8/1 a factor is Something multiplied together which means that as we started we have to scale it down that means that whatever we multiply by hast to make the answer smaller. That means that instead of scaling by 8 we’re going to scale by 1/8
Answer:
and then we have:
Step-by-step explanation:
From the info given by the problem we need an integer defined as the smallest positive integer that is a multiple of 75 and have 75 positive integral divisors, and we are assuming that 1 is one possible divisor.
Th first step is find the prime factorization for the number 75 and we see that
And we know that 3 =2+1 and 5=3+2 and if we replace we got:
And in order to find 75 integral divisors we need to satisify this condition:
such that 
For this case we have two prime factors important 3 and 5. And if we want to minimize n we can use a prime factor like 2. The least common denominator between 2 and 4 is LCM(2,4) =4. So then the need to have the prime factors 2 and 3 elevated at 4 in order to satisfy the condition required, and since 5 is the highest value we need to put the same exponent.
And then the value for n would be given by:
and then we have:
Let A be some subset of a universal set U. The "complement of A" is the set of elements in U that do not belong to A.
For example, if U is the set of all integers {..., -2, -1, 0, 1, 2, ...} and A is the set of all positive integers {1, 2, 3, ...}, then the complement of A is the set {..., -2, -1, 0}.
Notice that the union of A and its complement make up the universal set U.
In this case,
U = {1, 2, 3, 6, 10, 13, 14, 16, 17}
The set {3, 10, 16} is a subset of U, since all three of its elements belong to U.
Then the complement of this set is all the elements of U that aren't in this set:
{1, 2, 6, 13, 14, 17}
