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laiz [17]
3 years ago
13

What transformation is described by the notation (x, y) to (x, -y)?

Mathematics
1 answer:
ivanzaharov [21]3 years ago
5 0

Answer:

is rotation one of them

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Can you plz help me as soon as possible plz help me plz ASAP
katovenus [111]

Answer:

the answer is c:  7 feet 7 inches

Step-by-step explanation:

5 0
3 years ago
X + y = 18 y = 3x+6 i need help on this pls
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Step-by-step explanation:

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4 0
2 years ago
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Can be used to compare changes from one period to another.
vlada-n [284]

Answer:

c) Percentages

Step-by-step explanation:

Percentages can be used to compare changes from one period to another.

In calculating a percentage change, either a percentage increase or percentage decrease, we must have both the new and old measurement of the specific quantity.

For example, let's find percentage increase of the number of students that joined a book club using the parameters below;

Original number of students = 32

New number of students = 36

We will calculate the increase using;

Increase = original \; number  -  new \; number

Substituting the values, we have;

Increase = 36 - 32 = 4

Percentage \; increase = \frac{increase}{original \; number} * 100

Percentage \; increase = \frac{4}{32} * 100

Percentage \; increase = 0.125 * 100

Percentage increase = 12.5%

Therefore, the number of students in the school club increased by 12.5%.

8 0
3 years ago
Previously, an organization reported that teenagers spent 4.5 hours per week, on average, on the phone. The organization thinks
Fudgin [204]

Answer:

The teenagers spent 4.5 hours per week, on average, on the phone.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 4.5

Sample mean, \bar{x} = 4.75

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation, s = 2

First, we design the null and the alternate hypothesis

H_{0}: \mu = 4.5\text{ hours per week}\\H_A: \mu > 4.5\text{ hours per week}

We use one-tailed(right) t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{4.75 - 4.5}{\frac{2}{\sqrt{15}} } = 0.4841

Now,

t_{critical} \text{ at 0.05 level of significance, 14 degree of freedom } = 1.76

Since,                  

t_{stat} < t_{critical}

We accept the null hypothesis.  Thus, the teenagers spent 4.5 hours per week, on average, on the phone. The sample contradicted the organization's claim.

7 0
3 years ago
What is 9×1+2×1/10+6×1 100 written in standard form
levacccp [35]

Answer:

600+0+9+0.2

Step-by-step explanation:

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3 years ago
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