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pochemuha
3 years ago
13

Complete the square to re-write the quadratic function vertex form:y=x2 + 4x + 4​

Mathematics
1 answer:
ankoles [38]3 years ago
3 0

Answer:

Step-by-step explanation:

y=x²+4x+4

or y=(x+2)²

or y=(x+2)²+0

vertex Is (-2,0)

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Help, I need #2,3, and 4.
vredina [299]
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6 0
3 years ago
Help please! I already know the answer isn't -2, -1 so I need help figuring out the rest!
Lelu [443]

the function is increasing from x = 0 to x = 1

when x = 0, y = 2

when x = 1, y = 8

this shows an increase of +6, so we know this statement is true

we can see the rest are false simply because they state a decrease when there is an increase. this question is only confusing because we ask you about the increase and decrease in the function, when really its the same thing as asking about an increase or decrease in the y variable.

in other words, all youre looking for is the variation of the value of the y variable that is attached to the specific x variables.

hope this helps!!

8 0
2 years ago
When x+2 = 1/5y is written in standard form, what is the value or B
Ket [755]

Answer:

B=-1

Step-by-step explanation:

Standard form is Ax+By=C.

In this case, Ax is x, By is 1/5y, and C is +2.

To isolate the 2 (the C), subtract x from both sides of the equation:

x+2=1/5y

-x     -x

2=-x+1/5y.

Now, the value of B, the x value, is -1.

4 0
3 years ago
Complete the statement using always, sometimes, or never.
Fynjy0 [20]
I believe that, "A quadrilateral is sometimes a trapezoid”.
5 0
3 years ago
the half-life of strontium-90 is approximately 29 years. how much of a 500 g sample of strontium-90 will remain after 58 years​
Yuliya22 [10]

Answer:  125 g

<u>Step-by-step explanation:</u>

A = P_o\cdot e^{kt}\\\\\text{First, use the given information to find k:}\\\\\bullet A=\dfrac{1}{2}P_o\\\\\bullet k = unknown\\\\\bullet t=29\text{ years}\\\\\dfrac{1}{2}P_o=P_o\cdot e^{k(29)}\\\\\\\dfrac{1}{2}=e^{k(29)}\qquad divided\ both\ sides\ by\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=ln\bigg(e^{k(29)}\bigg)\qquad applied\ ln\ to\ both\ sides\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=29k\qquad simplified-ln\ and\ e\ cancel\ out\\\\\\\dfrac{ln\bigg(\dfrac{1}{2}\bigg)}{29}=k\qquad divided\ 29\ from\ both\ sides\\\\\\-0.0239=k

\text{Now, use the following in the equation to solve for A:}\\\\\bullet A=unknown\\\bullet P_o=500\\\bullet k=-0.0239\\\bullet t=58\text{ years}\\\\A=500\cdot e^{(-0.0239)(58)}\\\\.\quad=500\cdot e^{-1.386}\\\\.\quad=125

8 0
3 years ago
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