What is the length of the transverse axis of the conic section show below ? (y+2)^2/16-(x-3)^2/9=1
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<h2>Answer </h2>
The length of UC is 18
<h2>Explanation </h2>First we are going to find the length of JN; then we are subtracting from it the length of JU plus the length of CN.
We can infer from our picture that JN is 82 + 105, so JN = 187
We can also infer that JU = JH + HU
JU = 22 + 96
JU = 118
We can also infer that CN = 51
Now we can fin the length of UC:
We can conclude that the length of UC is 18.