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Nookie1986 [14]
4 years ago
10

3. use the law of exponents to evaluate (1/x) ^ -n when x= 7 and n= 2

Mathematics
1 answer:
emmainna [20.7K]4 years ago
8 0
D on both ...................
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The difference of Ann’s and Jay’s heights is half of
Svetach [21]

Answer:

The answer would H.

A = 1/2 j + j

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Rectangle A has a larger area

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The volume of the cone is 50π ft³. The height is 6 ft. What is the radius of the​ cone?
laila [671]

Answer:

r = 5 feet

Step-by-step explanation:

see attached for reference

recall that volume of a circular cone is given by

V = (1/3) πr²h, where

V = volume = given as 50π ft³

r = radius (we are asked to find this)

h = height of cone = given as 6 feet

Substituting the above known values into the equation:

V = (1/3) πr²h

50π = (1/3) π (r²)(6)

50π = π (r²)(2)  (divide both sides by 2)

25π = π r²   (divide both sides by π)

25 = r²

r = ±√25

r = ±5   (since radius cannot be negative, we select the positive value

r = 5 feet

3 0
4 years ago
PLEASE ANSWER ASAP!!!!!!
Romashka [77]

The range in the average rate of change in temperature of the substance is from a low temperature of 1 F to a high of -11 F.

<h3>What is a formula for Fahrenheit?</h3>

The conversion formula for a temperature that is expressed on the Celsius (°C) scale to its Fahrenheit (°F) ;

°F = (9/5 × °C) + 32.

Given function:

f(x)= -6 sin(7/3 x+ 1/6) -5

The function will be maximum at the 7/3 x +1/6= 3π/2

So, the maximum temperature will be

= -6 sin (3π/2) -5

= 6 -5

= 1 F

The function will be minimum at the 7/3 x +1/6= π/2

Therefore, the maximum temperature will be

= -6 sin (π/2) - 5

= -6 -5

= -11 F

Learn more about this concept here:

brainly.com/question/26172293

#SPJ1

5 0
2 years ago
Evaluate the surface integral. S xz dS S is the boundary of the region enclosed by the cylinder y2 + z2 = 16 and the planes x =
bagirrra123 [75]

If you project S onto the (x,y)-plane, it casts a "shadow" corresponding to the trapezoidal region

T = {(x,y) : 0 ≤ x ≤ 10 - y and -4 ≤ y ≤ 4}

Let z = f(x, y) = √(16 - y²) and z = g(x, y) = -√(16 - y²), each referring to one half of the cylinder to either side of the plane z = 0.

The surface element for the "positive" half is

dS = √(1 + (∂f/∂x)² + (∂f/dy)²) dx dy

dS = √(1 + 0 + 4y²/(16 - y²)) dx dy

dS = √((16 + 3y²)/(16 - y²)) dx dy

The the surface integral along this half is

\displaystyle \iint_T xz \,dS = \int_{-4}^4 \int_0^{10-y} x \sqrt{16-y^2} \sqrt{\frac{16+3y^2}{16-y^2}} \, dx \, dy

\displaystyle \iint_T xz \,dS = \int_{-4}^4 \int_0^{10-y} x \sqrt{16+3y^2}\, dx \, dy

\displaystyle \iint_T xz \,dS = \frac12 \int_{-4}^4 (10-y)^2 \sqrt{16+3y^2} \, dy

\displaystyle \iint_T xz \,dS = 416\pi

You'll find that the integral over the "negative" half has the same value, but multiplied by -1. Then the overall surface integral is 0.

8 0
3 years ago
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