3x(x+3)^2
3x(x^2 + 6x + 9)
= 3x^3 + 18x^2 + 27x
answer
3x^3 + 18x^2 + 27x
The given circles are given in standard form:
(x - xc)² + (y - yc)² = r²
The second quadrant is the one that has negative x coordinates and positive y coordinates.
This said, let's see all your options:
A) (x - 5)² + (y - 6)² = 25
xc = -(-5) = +5
yc = -(-6) = +6
C (5 , 6) is in the first quadrant.
B) (x + 1)² + (y - 7)² = 16
xc = -(+1) = -1
yc = -(-7) = +7
C (-1 , 7) is in the second quadrant.
C) (x - 4)² + (y + 3)² = 32
xc = -(-4) = +4
yc = -(+3) = -3
C (4, -3) is in the fourth quadrant.
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D) (x + 2)² + (y - 5)²= 9</span>
xc = -(+2) = -2
yc = -(-5) = +5
C (-2 , +5) is in the second quadrant.
Therefore, the correct answers are B and D.
Answer:
answer is 9
Step-by-step explanation:
p - ( q - (m +q) )
make m = 4
p = 5
q = 3
5 - ( 3 - ( 4+3) )
5 - ( 3 - 7 )
5 - - 4
= 9
Answer:
Step-by-step explanation:
P = 2w + 2l
l = 3 + w
38 = 2w + 2(3 + w)
38 = 2w + 6 + 2w
38 - 6 = 4w
32 = 4w
w = 32 : 4
w = 8 inches
l = 3 + w
l = 3inches + 8inches
l = 11 inches
