The solution of 
are 1 + 2i and 1 – 2i
<u>Solution:</u>
Given, equation is
We have to find the roots of the given quadratic equation
Now, let us use the quadratic formula
--- (1)
<em><u>Let us determine the nature of roots:</u></em>
Here in a = 1 ; b = -2 ; c = 5
Since 
, the roots obtained will be complex conjugates.
Now plug in values in eqn 1, we get,
On solving we get,
we know that square root of -1 is "i" which is a complex number
Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i
Answer:
C
Step-by-step explanation:
the equation of the parabola is : y = x² - 3x
the equation of the line is y = x + 1
and the shaded area is between those graphs
therefore y ≥ x² - 3x and y ≤ x + 1
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is going to be your answers i believe
Answer:
Thats smarttt
Step-by-step explanation:
You phrased it so it would get pass the brainly bots system, kudos to you!
Answer:
see explanation
Step-by-step explanation:
The n th term of an arithmetic progression is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given 
= 12 and 
= 22, then
a₁ + 5d = 12 → (1)
a₁ + 7d = 22 → (2)
Subtract (1) from (2) term by term to eliminate a₁
2d = 10 ( divide both sides by 2 )
d = 5
Substitute d = 5 into (1) to find a₁
a₁ + 5(5) = 12
a₁ + 25 = 12 ( subtract 25 from both sides )
a₁ = - 13
Thus
= - 13 + 5 = - 8
= - 13 + 5(n - 1) = - 13 + 5n - 5 = 5n - 18 ← n th term
