In binomial distribution,
n=sample size =69
p=probability of success = 0.29
mean = np = 69*.29= 20.0100
variance = npq = np(1-p) =20.01(1-0.29)=14.20710
standard deviation=sqrt(variance)=3.76923
(round to appropriate number of decimal places)
Answer:
w= a/3-4p
Step-by-step explanation:
3w+4p=a divide 3 on both sides
w+4p= a/3 subtract 4p on both sides
w= a/3-4p w is now isolated
The answer is that its vertical
Answer:
x = 4
Step-by-step explanation:
Given
= 5 ( multiply both sides by 3 to clear the fraction )
7 + 2x = 15 ( subtract 7 from both sides )
2x = 8 ( divide both sides by 2 )
x = 4
Answer/Step-by-step explanation:
Recall the acronym SOHCAHTOA. This is what we would apply as appropriate in each case.
8. θ = 40°
Opp = m
Adj = 20
Thus, apply TOA
Tan (θ) = opp/adj
Plug in the values
Tan (40) = m/20 (equation)
20×Tan(40) = m
m = 16.7820
9. θ = 22°
Hyp = w
Adj = 18
Thus, apply CAH
Cos (θ) = adj/hyp
Plug in the values
Cos 22 = 18/w (equation)
w×cos 22 = 18
w = 18/(cos 22)
w = 19.4136
10. θ = 35°
Hyp = 55
Opp = x
Thus, apply SOH
Sin θ = opp/hyp
Plug in the values
Sin 35 = x/55 (equation)
55×sin 35 = x
x = 31.5467
11. θ = 33°
Hyp = 19
Adj = x
Thus, apply CAH
Cos θ = adj/hyp
Plug in the values
Cos 33 = x/19 (equation)
19×cos 33 = x
x = 15.9347
12. θ = 17°
Opp = 7
Hyp = x
Thus, apply SOH
Sin θ = opp/hyp
Plug in the values
Sin 17 = 7/x (equation)
x×sin 17 = 7
x = 7/(sin 17)
x = 23.9421
13. θ = 40°
Opp = 15
Adj = x
Thus, apply TOA
Tan θ = opp/adj
Plug in the values
Tan 40 = 15/x (equation)
x×Tan 40 = 15
x = 15/(Tan 40)
x = 17.8763
