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2 years ago

12(8b - 5) ? Please need an awnser

Mathematics

2 answers:

andrew-mc [135]2 years ago

3 0

Distribute the 12 by multiplying so it would be 96b-60 and they aren’t like terms so that’s as far as you can go

Mashcka [7]2 years ago

3 0

Answer:

96b-60

Step-by-step explanation:

Distribute the 12 into the parantheses. 12*8b=96b and 12*-5=-60 so 96b-60.

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avanturin [10]

Answer:

A.) x / 3 = 12 ----> x = 12(3) ----> x = 36

B.) 2x + 3 = 20 ----> 2x = 17 ----> x = 17/2

C.) 4/3x = 10/3 ----> x = 10/3 x 3/4 ----> x = 30/12 = 5/2

D.) -4x = -24 ----> x = -24/-4 ----> x = 6

E.) 2(x-4) = 10 ----> 2x - 8 = 10 ----> 2x = 18 ----> x = 9

F.) -0.5x + 1.1 = -2.9 ----> -0.5x = -4 ---> x = -4 / -0.5 ----> x = 8

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2 years ago

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3 years ago

Read 2 more answers

Can anybody show me how to do this half angle identity problem STEP BY STEP? I always seem to be missing something

klio [65]

Answer: $\bold{-\dfrac{7\sqrt2}{10}}$

Step-by-step explanation:

It is given that θ is between 270° and 360°, which means that θ is located in Quadrant IV ⇒ (x > 0, y < 0). Furthermore, the half-angle will be between 135° and 180°, which means the half-angle is in Quadrant II ⇒ $cos\ \dfrac{\theta}{2}$

It is given that sin θ = $-\dfrac{7}{25}$ ⇒ y = -7 & hyp = 25

Use Pythagorean Theorem to find "x":

x² + y² = hyp²

x² + (-7)² = 25²

x² + 49 = 625

x² = 576

x = 24

Use the "x" and "hyp" values to find cos θ:

$cos\ \theta=\dfrac{x}{hyp}=\dfrac{24}{25}$

Lastly, input cos θ into the half angle formula:

$cos\bigg(\dfrac{\theta}{2}\bigg)=\pm \sqrt{\dfrac{1+cos\ \theta}{2}}\\\\\\.\qquad \quad =\pm \sqrt{\dfrac{1+\dfrac{24}{25}}{2}}\\\\\\.\qquad \quad =\pm \sqrt{\dfrac{\dfrac{25}{25}+\dfrac{24}{25}}{2}}\\\\\\.\qquad \quad =\pm \sqrt{\dfrac{\dfrac{49}{25}}{2}}\\\\\\.\qquad \quad =\pm \sqrt{\dfrac{49}{50}}\\\\\\.\qquad \quad =\pm \dfrac{7}{5\sqrt2}}\\\\\\.\qquad \quad =\pm \dfrac{7}{5\sqrt2}}\bigg(\dfrac{\sqrt2}{\sqrt2}\bigg)\\\\\\.\qquad \quad =\pm \dfrac{7\sqrt2}{10}$

Reminder: We previously determined that the half-angle will be negative.

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