Answer:The mass of an object is 52 kg.
Explanation:
Gravitational force on the object ,F=510 N
Acceleration due to gravity = g =
Mass of the object = m
Force = mass × acceleration
The mass of an object is 52 kg.
A car that travels from point A to point B in four hours, and then from point B back to point A in six hours. The road between p
2 answers:
Note : Be careful with speed and velocity, even the formula is same that 
1. If we would like to find the velocity, we must calculate the distance from initial to final,
,
2. If we would like to find the speed, we must calculate the total distance that travelled (
.
So, in this question, because it return back to its initial point so (delta)x = 0, so average velocity is 0 m/s.
1. If we would like to find the velocity, we must calculate the distance from initial to final,
2. If we would like to find the speed, we must calculate the total distance that travelled (
So, in this question, because it return back to its initial point so (delta)x = 0, so average velocity is 0 m/s.
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The resultant force on the positive charge is mathematically given as
X=40N
<h3>What is the magnitude of the electrostatic force on the negative charge?</h3>Question Parameters:
Three-point charges, two positive and one negative, each having a magnitude of 20
Generally, the -ve charge is mathematically given as
Q+=X
Therefore
X=40N
For more information on Force
Answer:
v_{f} = 115.95 m / s
Explanation:
This is an exercise of a variable mass system, let's form a system formed by the masses of the rocket, the mass of the engines and the masses of the injected gases, in this case the system has a constant mass and can be solved using the conservation the amount of movement. Which can be described by the expressions
Thrust =
-v₀ = v_{e}
where v_{e} is the velocity of the gases relative to the rocket
let's apply these expressions to our case
the initial mass is the mass of the engines plus the mass of the fuel plus the kill of the rocket, let's work the system in SI units
M₀ = 25.5 +12.7 + 54.5 = 92.7 g = 0.0927 kg
The final mass is the mass of the engines + the mass of the rocket
M_{f} = 25.5 +54.5 = 80 g = 0.080 kg
thrust and duration of ignition are given
thrust = 5.26 N
t = 1.90 s
Let's start by calculating the velocity of the gases relative to the rocket, where we assume that the rate of consumption is linear
thrust = v_{e}
v_{e} = thrust
v_{e} = 5.26
v_{e} = - 786.93 m / s
the negative sign indicates that the direction of the gases is opposite to the direction of the rocket
now we look for the final speed of the rocket, which as part of rest its initial speed is zero
v_{f}-0 = v_{e}
we calculate
v_{f} = 786.93 ln (0.0927 / 0.080)
v_{f} = 115.95 m / s