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DanielleElmas [232]
2 years ago
8

A car that travels from point A to point B in four hours, and then from point B back to point A in six hours. The road between p

oint A and point B is perfectly straight, and the distance between the two points is 240 km. What is the car’s average velocity?
Physics
2 answers:
Hitman42 [59]2 years ago
3 0
Note : Be careful with speed and velocity, even the formula is same that v =  \frac{x}{t}

1. If we would like to find the velocity, we must calculate the distance from initial to final, x_{f} -  x_{i} = (delta)x,

2. If we would like to find the speed, we must calculate the total distance that travelled (x_{total}.

So, in this question, because it return back to its initial point so (delta)x = 0, so average velocity is 0 m/s.
cestrela7 [59]2 years ago
3 0
If you mean average speed, it is 480/10 = 48 kn/h

If you mean average velocity, it is 0/10 = 0 km/h
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A 25N force is acting on a body moving on a straight line with Initial momentum 20 kam's. Find the final momentum after 4 second
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The final momentum of the body is equal to 120 Kg.m/s.

<h3>What is momentum?</h3>

Momentum can be described as the multiplication of the mass and velocity of an object. Momentum is a vector quantity as it carries magnitude and direction.

If m is an object's mass and v is its velocity then the object's momentum p is: {\displaystyle \mathbf {p} =m\mathbf {v} . The S.I. unit of measurement of momentum is kg⋅m/s, which is equivalent to the N.s.

Given the initial momentum of the body = Pi = 20 Kg.m/s

The force acting on the body, Pf = 25 N

The time, Δt = 4-0 = 4s

The Force is equal to the change in momentum: F ×Δt = ΔP

25 × 4 = P - 20

100 = P - 20

P = 100 + 20 = 120  Kg.m/s

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A force acting on a body causes a change in the momentum of the from 12 kgms-1 to 16 kgms-1 in 0.2 s. calculate the magnitude of
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Substitute P1 and P2 into the formula

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