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Nuetrik [128]
3 years ago
7

The combining of light nuclei is called blank. Blank as in ____. Not actually blank. You know what im tryin to say.

Physics
2 answers:
Andreas93 [3]3 years ago
6 0

Answer:

The combining of light nuclei is called nuclear fusion.

lisov135 [29]3 years ago
6 0

Answer:

Fusion

Explanation:

The combination of two lighter nuclie and forms a new heavier nucleus and release and lot of amount of energy is called nuclear fusion.

To start the nuclear fusion reaction we need a very high temperature.

We get energy from sun, it is due to the nuclear fusion of hydrogen and forms helium.

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When energy is added to a wave, how can the wave change?.
nadya68 [22]

Answer:

When waves overlap in-phase (crest meets crest or trough meets trough) the waves energy is additive and the amplitude increases.

Explanation:

When waves overlap out-of-phase (crest meets trough) the waves cancel and the amplitude (energy) decreases. When two interfering waves cancel each other out.

6 0
2 years ago
The period of an ocean wave is 5 seconds. What is the wave's frequency?
Oksana_A [137]

Answer:

f=1/5= 0.2 Hz

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7 0
3 years ago
The energy delivered to the resistive coil is dissipated as heat at a rate equal to the power input of the circuit. However, not
Nata [24]

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4 0
3 years ago
A 1.00 kg object moving in the + x direction at 10.0 m/s collides with a 1.50 kg object traveling at 5.00 m/s in the - x directi
marysya [2.9K]

Answer:

The amount of kinetic energy lost during the collision is 60.75 J

Explanation:

The given parameters are;

The mass of the object moving in the +x direction, m₁ = 1.00 kg

The velocity of the object moving in the +x direction, v₁ = 10.0 m/s

The mass of the object moving in the -x direction, m₂ = 1.50 kg

The velocity of the object moving in the +x direction, v₂ = 5.00 m/s

The final velocity of the 1.00 kg mass after collision, v₃ = 4.00 m/s

The direction of motion of the 1.00 kg mass after collision = -x direction

The total initial kinetic energy of the system, K.E._{total \ initial} = 1/2·m₁·v₁² + 1/2·m₂·v₂²

∴ K.E._{total \ initial}  = 1/2×1.00×10² + 1/2×1.50×5² = 68.75 J

The final kinetic energy of the system, K.E._{final}  = 1/2·m₁·v₃²

K.E._{final} = 1/2×1.00×4² = 8 J

The amount of kinetic energy lost during the collision, \Delta K.E._{system} is given as follows;

\Delta K.E._{system} =  K.E._{final} -K.E._{total \ initial} = 8 J - 68.75 J = -60.75 J

The amount of kinetic energy lost during the collision = 60.75 J.

7 0
3 years ago
If one knows only the constant resultant force acting on an object and the time during which this force acts, one can determine
yawa3891 [41]
Answer is number 2, change in momentum of the object.
3 0
3 years ago
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