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3 years ago

The combining of light nuclei is called blank. Blank as in ____. Not actually blank. You know what im tryin to say.

Physics

2 answers:

Andreas93 [3]3 years ago

6 0

Answer:

The combining of light nuclei is called nuclear fusion.

lisov135 [29]3 years ago

6 0

Answer:

Fusion

Explanation:

The combination of two lighter nuclie and forms a new heavier nucleus and release and lot of amount of energy is called nuclear fusion.

To start the nuclear fusion reaction we need a very high temperature.

We get energy from sun, it is due to the nuclear fusion of hydrogen and forms helium.

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How much thermal energy does it take to raise the temperature of 3.5 kg of water from 25°C to 46°C? The specific heat of water i

Alex_Xolod [135]

Q = mcΔT

Q = (3.5)(4.18)(46-25)

Q = 307.23 kJ

6 0

3 years ago

Read 2 more answers

Calculate the Energy (E) in joules for that wavelength and record it in the table below. Remember that E = HF, where h the Planc

Viefleur [7K]

In that formula for Energy, 'F' is the frequency of the photon.
But Frequency = (speed)/(wavelength), so we can write the
Energy formula as
 E = h c / (wavelength) .

So the energy, in joules, of a photon with that wavelength, is . . .

 E = (6.6 x 10⁻³⁴) x (3 x10⁸) / (that wavelength)

 = (1.989 x 10⁻²⁵) / (that wavelength, in meters) .

5 0

3 years ago

The Kinetic energy, K, of an object with mass m moving with velocity v can be found using the formula - E_{\text{k}}={\tfrac {1}

tester [92]

Answer:

The ratio of kinetic energies of 5 kg object to 20 kg object is 1:1.

Explanation:

Kinetic energy is defined as energy possessed by an object due to its motion.It is calculated by:

$K.E=\frac{1}{2}mv^2$

Kinetic energy of the 5 kg object.

Mass of object,m = 5 kg

Velocity of an object = v

$K.E=\frac{1}{2}mv^2=\frac{1}{2}\times 5kg\times v^2$

Kinetic energy of the 20 kg object.

Mass of object,m' = 20 kg

Velocity of an object = v'

$K.E=\frac{1}{2}mv^2=\frac{1}{2}\times 20kg\times v'^2$

The ratio of the kinetic energy of the 5 kilogram object to the kinetic energy of the 20-kilogram object:

$\frac{K.E}{K.E'}=\frac{\frac{1}{2}\times 5kg\times v^2}{\frac{1}{2}\times 20kg\times v'^2}$

Given that, v = 2v'

$\frac{K.E}{K.E'}=\frac{1}{1}$

The ratio of kinetic energies of 5 kg object to 20 kg object is 1:1.

3 0

3 years ago

an electric current of 285.0 ma flows 674. milliseconds. Calculate the amount of electric charge transported. Be sure your answe

yulyashka [42]

Answer:

The amount of electric charge transported = 0.192 C

Explanation:

Electric Charge: This is defined as the product of electric current and time in an electric circuit, The S.I unit of electric charge is Coulombs (C)

Q = It..................... Equation 1

Where Q = Electric charge, I = electric current, t = time.

Given: I = 285 mA, t = 674 milliseconds.

Conversion: (i) Convert from 285 mA to A = (285/1000) A = 0.285 A

(ii) convert from 674 milliseconds to seconds = (674/1000) s = 0.674 s

Substituting these values into equation 1

Q = 0.285 × 0.674

Q = 0.192 C

Therefore the amount of electric charge transported = 0.192 C

5 0

2 years ago

An object is hung from a spring balance attached to the ceiling of an elevator cab. The balance reads 65 N when the cab is stand

lana66690 [7]

Answer:

(A) Reading will be 65 N

(B) Net force on the elevator will be 49.076 N

Explanation:

We have given the balance force = 65 N

Acceleration due to gravity $g=9.8m/sec^2$

We know that W=mg

So $65=m\times 9.8$

m = 6.632 kg

(a) In first case as the as the speed is constant so the force on the elevator will be 65 N

(B) In second case as the elevator is decelerating at a rate of $2.4m/sec^2$

So net acceleration = 9.8-2.4= $7.4m/sec^2$

So net force on elevator will be = m× net acceleration = 6.632×7.4 = 49.076 N

7 0

3 years ago