During cellular respiration, organisms use oxygen to turn glucose into carbon dioxide, water, and energy in the form of ATP. The process has three stages: glycolysis , the Krebs cycle, and the electron transport chain. Glycolysis in the cytoplasm ), breaks down 1 glucose into 2 pyruvate and 2 ATP. The Krebs cycle (in the mitochondrion's matrix), provides the hydrogen and electrons needed for the electron transport chain. Another 2 are formed here. The electron transport chain (on the inner mitochondrial membrane) forms 32 ATP through oxidative phosphorylation .
Answer:
snow is 64.638 kg / hr
Explanation:
Given data
wide w = 21 feet
long L = 20 ft
area A = 1350 square foot
mass of snow m = 1.90 mg
to find out
snow in kilograms / hour
solution
we will find snow in kg
so we apply formula that is
snow kg / hour = w × L ×A × m × 60/10^6
put all value we get snow
snow = 21 × 20 × 1350 × 1.90 × 60/10^6
snow = 420 × 1350 × 1.90 × 60/10^6
snow = 1077300 × 60/10^6
snow = 64.638
hence snow is 64.638 kg / hr
<span>Phase, color, and ductility are all examples of physical external properties</span>
Answer:
c. streak
Explanation:
Pyrite is a mineral that looks like gold but actually is iron disulfide.
Pyrite and gold have comparable luster.
Pyrite and gold have different tones of yellow. This can be determined by their streak. Streak is the powdered form of a mineral. A streak of mineral can be found just by rubbing the mineral on a rough surface and comparing the colors.
Pyrite is diamagnetic which is not a strong form of magnetism. Gold is also diamagnetic
Answer:
2f
Explanation:
The formula for the object - image relationship of thin lens is given as;
1/s + 1/s' = 1/f
Where;
s is object distance from lens
s' is the image distance from the lens
f is the focal length of the lens
Total distance of the object and image from the lens is given as;
d = s + s'
We earlier said that; 1/s + 1/s' = 1/f
Making s' the subject, we have;
s' = sf/(s - f)
Since d = s + s'
Thus;
d = s + (sf/(s - f))
Expanding this, we have;
d = s²/(s - f)
The derivative of this with respect to d gives;
d(d(s))/ds = (2s/(s - f)) - s²/(s - f)²
Equating to zero, we have;
(2s/(s - f)) - s²/(s - f)² = 0
(2s/(s - f)) = s²/(s - f)²
Thus;
2s = s²/(s - f)
s² = 2s(s - f)
s² = 2s² - 2sf
2s² - s² = 2sf
s² = 2sf
s = 2f
