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3 years ago

Simplify. 3+ (-2) • 6

Mathematics

1 answer:

mojhsa [17]3 years ago

7 0

Step-by-step explanation:

$3 + ( - 2) \ast6 \\ = 3 + ( - 2 \times 6) \\ = 3 + ( - 12) \\ = 3 - 12 = - 9$

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What is the equation of the graph shown?

Elina [12.6K]

Answer:

(-6,1) I guess...

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3 years ago

PLEASE HELP!!!!!!! A family has two cars. The first car has a fuel efficiency of 35 miles per gallon of gas and the second has a

Marianna [84]

Answer:

The answer to your question is car 1 = 30 gal and car 1 = 20 gal

Step-by-step explanation:

car 1 = a

car 2 = b

Efficiency of car 1 = 35 mi/gal

Efficiency for car 2 = 20 mi/gal

Total distance = 1450

Total gas consumption = 50 gal

Equations

35a + 20b = 1450 ------- (I)

a + b = 50 ------- (II)

Solve by elimination

Multiply equation II by -35

35a + 20b = 1450

-35a - 35b = -1750

Simplify

0 - 15b = -300

Solve for b

b = -300/-15

Result

b = 20

Substitute b in equation II to find a

a + 20 = 50

Solve for a

a = 50 -20

Result

a = 30

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3 years ago

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Answer:4 in each package

Step-by-step explanation:

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3 years ago

F(t)=t^2+19t+60<br> What are the zeros of the function and what is the vertex of the parabola?

SVEN [57.7K]

Answer: $-4,-15;\ \left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

Step-by-step explanation:

Given

Function is $F(t)=t^2+19+60$

Zeroes of the function are

$t^2+19t+60=0\\\\\Rightarrow t=\dfrac{-19\pm\sqrt{19^2-4\times 1\times 60}}{2\times 1}\\\\\Rightarrow t=\dfrac{-19\pm \sqrt{121}}{2}\\\\\Rightarrow t=\dfrac{-19\pm 11}{2}\\\\\Rightarrow t=-4,-15$

Using completing the square method

$y=t^2+2\times \dfrac{19}{2}t+\dfrac{19^2}{2^2}-\dfrac{19^2}{2^2}+60\\\\y=\left(t+\dfrac{19}{2}\right)^2+60-\dfrac{361}{4}\\\\y=\left(t+\dfrac{19}{2}\right)^2-\dfrac{121}{4}\\\\y+\dfrac{121}{4}=\left(t+\dfrac{19}{2}\right)^2\\\\\left(y-(-\dfrac{121}{4}\right)=\left(t-(-\dfrac{19}{2})\right)^2\\\\\text{The vertex is }\left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

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3 years ago

How to write six billion sixty- seven million four hundred four thousand thirteen and nineteen thousandths in standard form?

Neko [114]

Standard for would be 6,670,404,013.19

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3 years ago