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3 years ago

Simplify. 3+ (-2) • 6

Mathematics

1 answer:

mojhsa [17]3 years ago

7 0

Step-by-step explanation:

$3 + ( - 2) \ast6 \\ = 3 + ( - 2 \times 6) \\ = 3 + ( - 12) \\ = 3 - 12 = - 9$

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Jillian is trying to save water, so she reduces the size of her square grass lawn by 8 feet on each side the area of the smaller

horsena [70]

Answer: 20 feet by 20 feet.

Step-by-step explanation:

1. You know that $x$ is the original measure of one side. Since it is a square, all its sides are equal.

2. Therefore, to solve the problem you only need to solve for $x$ , as you can see below:

- You have that:

$(a-b)^{2}=a^{2}-2ab+b^{2}$

- Then, you obtain the following quadratic equation:

$(x-8)^{2} =144\\x^{2}-2(x)(8)+8^{2}=144\\x^{2}-16x-80=0$

- Apply the Quadratic formula to solve it:

$x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}\\a=1\\b=-16\\c=-80$

- Then, you obtain:

$x_1=20\\x_2=-4$

3. The dimensions cannot be negative, therefore, the answer is: 20 feet by 20 feet.

3 0

3 years ago

Read 2 more answers

Select the correct answer. What is the domain of the function represented by this graph?

devlian [24]

Answer:

Doman is the x intercpet range

Step-by-step explanation:

all real numbers is the domain since the function goes on and on forever and will at one point get to 1 billion or trillion or just on and on forever.

8 0

3 years ago

If angle a has the terminal ray that falls in the fourth quadrant and cosine a equals 5/9 then determine the value of sin a in s

Tema [17]

Answer: $-\dfrac{2\sqrt{14}}{9}$

Step-by-step explanation:

Given

$\cos a=\dfrac{5}{9}$

$a$ lies in the fourth quadrant

So, sine must be negative in the fourth quadrant

Using identity $\sin ^2 x+\cos^2 x=1$ to find sine value

$\Rightarrow \sin^2 a=1-\dfrac{5^2}{9^2}$

$\\\\\Rightarrow \sin^2 a=1-\dfrac{25}{81}\\\\\\\Rightarrow \sin^2 a=\dfrac{56}{81}\\\\\\\Rightarrow \sin a=-\sqrt{\dfrac{56}{81}}\\\\\\\Rightarrow \sin a=-\dfrac{2\sqrt{14}}{9}$