x = 40/2 = 20 i think thsts the answer if I was wrong you have to right to slap my face
Ax^2+bx+c=0 is the standard form, so we add 5 to both sides to get
1*x^2+(-10)x+21=0
Answer:
1 & 4 are proportional to each other, if that helps at all!
Step-by-step explanation:
Factor by grouping.
0 = (x^3 +4x^2) +(9x +36) = x^2(x+4) +9(x+4) = (x^2+9)(x+4)
The first factor is the difference of squares (in complex numbers), so the form for factoring that can be used:
a^2 - b^2 = (a -b)(a +b)
Here, a=x, b=3i.
Then the factorization in complex numbers is
0 = (x -3i)(x +3i)(x +4)
Solutions are the values of x that make these factors be zero.
x = -4, -3i, 3i
I think it’s a had it before
