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loris [4]
3 years ago
6

Can someone please help me???!!!

Mathematics
1 answer:
Ksju [112]3 years ago
5 0

Answer:

I can't show you all of the work but you can use this to find the answer

https://www.mathsisfun.com/geometry/circle-theorems.html

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Trigonometry
Leona [35]

Answer:

7 units

Step-by-step explanation:

These points lie on the same horizontal line.

No vertical distance

Only horizontal distance of:

15-8 = 7 units

6 0
4 years ago
Read 2 more answers
1. 248 + 56 base 8 2. 751 +24 base 4 3. 1001 _ 111 base 3 4.3121 _1334 base 5 5. 321 ×21 base 5 6. 205+ 51 base 6​
liraira [26]

Answer:

If we are converting between two bases other than decimal, we typically have to convert ... For two digits in base 8, we need 4, 5, or 6 digits in base 2.

5 0
3 years ago
∆ ABC is similar to ∆DEF and their areas are respectively 64cm² and 121cm². If EF = 15.4cm then find BC.​
lyudmila [28]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

★ ∆ ABC is similar to ∆DEF

★ Area of triangle ABC = 64cm²

★ Area of triangle DEF = 121cm²

★ Side EF = 15.4 cm

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

★ Side BC

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

Since, ∆ ABC is similar to ∆DEF

[ Whenever two traingles are similar, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. ]

\therefore \tt \boxed{  \tt \dfrac{area( \triangle \: ABC )}{area( \triangle \: DEF)} =  { \bigg(\frac{BC}{EF} \bigg)}^{2}   }

❍ <u>Putting the</u><u> values</u>, [Given by the question]

• Area of triangle ABC = 64cm²

• Area of triangle DEF = 121cm²

• Side EF = 15.4 cm

\implies  \tt  \dfrac{64   \: {cm}^{2} }{12 \:  {cm}^{2} }  =  { \bigg( \dfrac{BC}{15.4 \: cm} \bigg) }^{2}

❍ <u>By solving we get,</u>

\implies  \tt    \sqrt{\dfrac{{64 \: cm}^{2} }{ 121 \: {cm}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \sqrt{\dfrac{{(8 \: cm)}^{2} }{  {(11 \: cm)}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \dfrac{8 \: cm}{11 \: cm}    =   \dfrac{BC}{15.4 \: cm}

\implies  \tt    \dfrac{8  \: cm \times 15.4 \: cm}{11 \: cm}    =   BC

\implies  \tt    \dfrac{123.2 }{11 } cm   =   BC

\implies  \tt   \purple{  11.2 \:  cm}   =   BC

<u>Hence, BC = 11.2 cm.</u>

{\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}

★ Figure in attachment.

\rule{280pt}{2pt}

4 0
2 years ago
Help ASAP! Need full rule
Ulleksa [173]
I dont know this one sorry
3 0
3 years ago
It is 30 points and will give brainliest
allochka39001 [22]

Answer:

4a2−4ab+b2

Step-by-step explanation:

(2a−b)2 =(2a+−b)(2a+−b)

=(2a)(2a)+(2a)(−b)+(−b)(2a)+(−b)(−b)  

 Sooo our equation =4a2−2ab−2ab+b2

Hoped I helped -

Sleepy~

7 0
3 years ago
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