Answer:
the x intercept is -4
Step-by-step explanation:
to find the x intercept, set y = 0 and solve for x
y = 5x+20
0 = 5x+20
subtract 20 from each side
-20 = 5x +20 -20
-20 = 5x
divide each side by 5
-20/5 = 5x/5
-4 =x
Answer:
The 6th term of the sequence is 25
Step-by-step explanation:
first term = a = 5
common difference = d = 4
The nth term of a sequence is
T_n = a + (n - 1)d
Therefore, the 6th term of the sequence is
T_6 = a + (6 - 1)d
T_6 = a + 5d
T_6 = 5 + 5(4)
T_6 = 5 + 20
T_6 = 25
<span>If there has to be 2 men and 2 women, we know
that we must take a group of 2 men out of the group of 15 men and a group of 2
women out of the group of 20 women. Therefore, we have:
(15 choose 2) x (20 choose 2)
(15 choose 2) = 105
(20 choose 2) = 190
190*105 = 19950
Therefore, there are 19950 ways to have a group of 4 with 2 men and 2women.</span>
<span>If there has to be 1 man and 3 women, we know
that we must take a group of 1 man out of the group of 15 men and a group of 3
women out of the group of 20 women. Therefore, we have:
(15 choose 1) x (20 choose 3)
(15 choose 1) = 15
(20 choose 3) = 1140
15*1140 = 17100
Therefore, there are 17100 ways to have a group of 4 with 3 women and 1 man.</span>
<span>We now find the total outcomes of having a group
with 4 women.
We know this is the same as saying (20 choose 4) = 4845</span>
Therefore, there are 4845 ways to have a group of
4 with 4 women.
We now add the outcomes of 2 women, 3 women, and
4 women and get the total ways that a committee can have at least 2 women.
19950 + 17100 + 4845 = 41895 ways that there will
be at least 2 women in the committee
