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Paul [167]
3 years ago
5

Michael perez deposited a total of $2000 with two savings institutions. one pays interest at a rate of 6%/year, whereas the othe

r pays interest at a rate of 7%/year. if michael earned a total of $136 in interest during a single year, how much did he deposit in each institution? (let x and y denote the amount of money, in dollars, invested at 6% and 7%, respectively.)
Business
1 answer:
White raven [17]3 years ago
7 0

Answer:

Amount invested at a rate of 6% = \$400

Amount invested at a rate of 7% = \$1600

Explanation:

Let x and y denote the amount of money, in dollars, invested at 6% and 7%, respectively.

Total amount deposited = $2000

x+y=2000

x=2000-y

Interest earned on amount x = \frac{6}{100}x

Interest earned on amount y = \frac{7}{100}y

Total interest earned =\frac{6}{100}x+\frac{7}{100} y

As Michael earned a total of $136 in interest during a single year,

\frac{6}{100}x+\frac{7}{100} y=136\\6x+7y=13600

Put x=2000-y

6(2000-y)+7y=13600\\12000-6y+7y=13600\\12000+y=13600\\y=13600-12000\\y=1600

So,

x=2000-1600=400

Amount invested at a rate of 6% = \$400

Amount invested at a rate of 7% = \$1600

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<em>Note that that the increase in material cost of $8 and the variable manufacturing overhead of $7 are relevant to the special order decision. Hence they are added.</em>

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The company should accept the special order, as it will increase its profit by $2,208

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image

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Explanation:

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