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7nadin3 [17]
2 years ago
8

The school events committee is planning to buy a banner and some helium balloons for graduation night. A store charges them $35

for the banner and $3 for each helium balloon. If the committee has at most $125 to spend, how many helium balloons can they buy
Mathematics
2 answers:
faust18 [17]2 years ago
7 0

Answer:

30 balloons

Step-by-step explanation:

Cost of banner = $ 35

Remaining amount after paying for banner = 125 - 35 = $90

Number of balloons = Remaining amount ÷ cost of one balloon

= 90 ÷ 3

 = 30

Nat2105 [25]2 years ago
3 0

Answer:

30 baloons

Step-by-step explanation:

1. Remove the price of the banner from the total amount you can spend.  You should then end up with $90

2.  Divide 90 by 3, because each balloon costs $3.  You should end up with 30.

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Determine the x-intercept and the y-intercept for the graph of this equation:<br> 2x - 3y + 36 = 0
natali 33 [55]

QUESTION:- DETERMINE THE X-INTERCEPT AND THE Y-INTERCEPT FOR THE GRAPH OF THE EQUATION.

EQUATION:- 2x - 3y + 36 = 0

STANDARD EQUATION:- y=mx+c

where

  1. m-> slope.
  2. c-> Y-INTERCEPT
  3. x&y are the coordinates.

SO GIVEN EQUATION:- 2x - 3y + 36 = 0

WE CAN SOLVE THIS TO CHANGE IN FORMAT OF STANDARD EQUATION

2x - 3y + 36 = 0 \\ 2x + 36 =3y \\ y =  \frac{2}{3} x +  \frac{36}{3}  \\ y =  \frac{2}{3} x +  \frac{ \cancel{36}^{ \:  \: 12} }{ \cancel3}  \\ y =  \frac{2}{3} x +  12 \\

SO :-

m =  \frac{2}{3}  \\ y - intercept = 12 \: ans

slope =  \frac{y2 - y1}{x2 - x1}  \\  \frac{2}{3}  =  \frac{0  - 12}{x  - 0}  \\ 2x = ( - 12) \times 3 \\ x =  \frac{ -  \cancel{12}^{ \:  \: 6} \times 3 }{ \cancel{2}} \\  x =  - 18 \:  \: ans

7 0
3 years ago
Jill has an old bike. her parents gave her 40$ to repair it new tires is 21$ she also wants to buy a bell 5$ and a basket 13$ ho
dimaraw [331]

Answer:

She will have 1$ left

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Is there another word for thesourous?????
scoundrel [369]

Answer:

   reference book.

   glossary.

   lexicon.

   onomasticon.

   terminology.

   vocabulary.

   language reference book.

   sourcebook.

Step-by-step explanation:

5 0
2 years ago
Suppose lines EF and GH are reflected over the line Y equals X to form the lines JK and LM which statement would be true about t
katrin [286]

Answer:

A) JK and LM will be parallel to each other.

Step-by-step explanation:

On reflection on y=x line the x co-ordinate changes with y co-ordinate and y co-ordinate changes with x co-ordinate

(x,y)\rightarrow (y,x)

Points on line EF

(0,6) , (-5,-2)

On reflection of this line on y=x the new points we get for line JK are

(6,0),(-2,-5)

Points on line GH

(-4,9),(-9,1)

On reflection on y=x line the new points we get for line LM are

(9,-4),(1,-9)

Slope of line JK

m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-5)-0}{(-2)-6} \\m=\frac{-5}{-8}=\frac{5}{8}

Slope of line LM

m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-9)-(-4)}{1-9} \\m=\frac{-9+4}{-8}=\frac{-5}{-8}\\m=\frac{5}{8}

For two line to be parallel, their slopes will be same.

m_{JK} =\frac{5}{8} , m_{LM}=\frac{5}{8}

Since slopes of lines JK and LM are same therefore we can say that these are parallel to each other.

5 0
3 years ago
Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo
natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

So

P(B) is the probability of the person having cancer, so P(B) = 0.009

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So P(A/B) = 0.91

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765

What is the probability that the person actually does have cancer?

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213

There is a 12.13% probability that the person actually does have cancer.

3 0
3 years ago
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