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3 years ago

A bee lands on a random point on a ruler edge. find the probability that the point is between 3 and 5.

2 answers:

6 0

It would be 1/4 because there are 12 inches on a ruler. And if it lands between 3 and 5 there are 3 chances out of 12 that it will land between 3 and 5. 3/12 simplifies to 1/4

Nuetrik [128]3 years ago

3 0

Answer: the correct answer was 1/6. I just got it right.

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Adding all the area.

we get : x^2 + 6x +8

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yanalaym [24]

$h=3+30t-5t^2\implies 13=3+30t-5t^2\implies 0=-10+30t-5t^2 \\\\\\ 5t^2-30t+10=0\implies 5(t^2-6t+2)=0\implies t^2-6t+2=0$

now, it doesn't give us nice looking integers, so let's plug that into the quadratic formula.

$~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{1}t^2\stackrel{\stackrel{b}{\downarrow }}{-6}t\stackrel{\stackrel{c}{\downarrow }}{+2}=0 ~\hspace{10em} t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ t= \cfrac{ - (-6) \pm \sqrt { (-6)^2 -4(1)(2)}}{2(1)}\implies t=\cfrac{6\pm\sqrt{36-8}}{2}$

$t=\cfrac{6\pm\sqrt{28}}{2}\implies t=\cfrac{6\pm\sqrt{2^2\cdot 7}}{2}\implies t=\cfrac{6\pm 2\sqrt{7}}{2}\implies t=\cfrac{2(3\pm 1\sqrt{7})}{2} \\\\\\ t=3\pm \sqrt{7}\implies t= \begin{cases} 3+\sqrt{7}\\ 3-\sqrt{7} \end{cases}\implies t\approx \begin{cases} 5.65\\ 0.35 \end{cases}$

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3 years ago