Answer:
The first term of the geometric series is 1
Step-by-step explanation:
In this question, we are tasked with calculating the first term of a geometric series, given the common ratio, and the sum of the first 8 terms.
Mathematically, the sum of terms in a geometric series can be calculated as;
S = a(r^n-1)/( r-1)
where a is the first term that we are looking for
r is the common ratio which is 3 according to the question
n is the number of terms which is 8
S is the sum of the number of terms which is 3280 according to the question
Plugging these values, we have
3280 = a(3^8 -1)/(3-1)
3280 = a( 6561-1)/2
3280 = a(6560)/2
3280 = 3280a
a = 3280/3280
a = 1
Okay I am not 100% sure because that is an extremely confusing question. But here is what I got.
(A) 2c² = 2bc + ac/2 Given
(B) 4c² = 2bc + ac Multiplication and Distribution
(C) 4c = 4b + a Division and Distribution
(D) 4c - a + 4b Subtraction
(E) 4b = 4c - a Symmetric
Answer:
(4+5)+(3+3) because you have eto break up the numbers
Answer:
The answer is C.
Step-by-step explanation: The number between 0 and 1. Think of decimals as cents, 100 cents makes a whole. So the number will be greater than 0 but less than 100.
The answer is D. dividing both sides by 4 isolates the variable
