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3 years ago

A bee lands on a random point on a ruler edge. find the probability that the point is between 3 and 5.

2 answers:

6 0

It would be 1/4 because there are 12 inches on a ruler. And if it lands between 3 and 5 there are 3 chances out of 12 that it will land between 3 and 5. 3/12 simplifies to 1/4

Nuetrik [128]3 years ago

3 0

Answer: the correct answer was 1/6. I just got it right.

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Please help and show work

Artemon [7]

Answer:

175 is the answer

Step-by-step explanation:

5x5=25

25x7=175

6 0

3 years ago

Employee I has a higher productivity rating than employee II and a measure of the total productivity of the pair of employees is

Schach [20]

Answer:

The variance of the measure of productivity = 141.67(to 2 d.p)

Step-by-step explanation:

The complete question and the step-by step explanation are contained in the files attached to this solution.

8 0

2 years ago

Determine the slope of the table

AURORKA [14]

Answer:

The slope is -1/2 or -0.5

Hope this helps!

5 0

2 years ago

Read 2 more answers

Can someone pls help me on 4 and 5

never [62]

Answer (4):

a=ub/k because

u=ak/b (starting equation)

ub=ak (multiply b to both sides)

a=ub/k (divide both sides by k)

Answer (6)

x=g+c-y because

g=x-c+y (starting equation)

x+y=g+c (add c to both sides)

x=g+c-y (subtract y from both sides)

5 0

3 years ago

In a random sample of 30 people who rode a roller coaster one day, the mean wait time is 46.7 minutes with a standard deviation

Rainbow [258]

Answer: C. $(29,\ 37.8)$

Step-by-step explanation:

The confidence interval for difference of two population mean is given by :-

$\overline{x}_1-\overline{x}_2\pm z_{\alpha/2}\sqrt{\dfrac{s_1^2}{n_1}+\dfrac{s_2^2}{n_2}}$

Given : Level of significance : $1-\alpha:0.99$

Then , significance level : $\alpha: 1-0.99=0.01$

Critical value : $z_{\alpha/2}=z_{0.005}=2.576$

$n_1=30\ ;\ n_2=50\\\\\overline{x}_1=46.7\ ;\ \overline{x}_2=13.3\\\\s_1=9.2\ ;\ s_2=1.9$

$46.7-13.3\pm(2.576)\sqrt{\dfrac{9.2^2}{30}+\dfrac{1.9^2}{50}}\approx33.4\pm4.38=(29.02\ ,37.78)\approx(29,\ 37.8)$

Hence, a 99% confidence interval for the difference between the mean wait times of everyone who rode both rides $(29,\ 37.8)$

5 0

3 years ago