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Nata [24]
3 years ago
12

Also called regrouping this is when adding numbers results in more than two digits and one digit is placed in the colum to the l

eft
Mathematics
1 answer:
kotykmax [81]3 years ago
6 0

Answer:

Carrying forward.

Step-by-step explanation:

  • When regrouping is done to add the numbers where results in a more than 2 digit and one digit is placed to left Colum is called as carrying forward. As regrouping refers to carrying the place values in order to perform operations like addition or subtraction.
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Graph y≤1−3x. brianly
Daniel [21]

Answer:

B

Step-by-step explanation:

\leq means everything to the left of, and also everything on the line since it's equal to as well, so B is the correct answer

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$1800 is invested at 4% compounded annually. Find the future value of the investment in 5 years. Find the interest that the inve
harina [27]
5 Years is 1800x1.04^5 = 2189.98
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A discrete sample space is one in which outcomes are counted.<br> True<br> False
icang [17]
The answer to your question is True.
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2 years ago
Find the exact length of the curve. 36y2 = (x2 − 4)3, 5 ≤ x ≤ 9, y ≥ 0
IrinaK [193]
We are looking for the length of a curve, also known as the arc length. Before we get to the formula for arc length, it would help if we re-wrote the equation in y = form.

We are given: 36 y^{2} =( x^{2} -4)^3
We divide by 36 and take the root of both sides to obtain: y = \sqrt{ \frac{( x^{2} -4)^3}{36} }

Note that the square root can be written as an exponent of 1/2 and so we can further simplify the above to obtain: y =  \frac{( x^{2} -4)^{3/2}}{6} }=( \frac{1}{6} )(x^{2} -4)^{3/2}}

Let's leave that for the moment and look at the formula for arc length. The formula is L= \int\limits^c_d {ds} where ds is defined differently for equations in rectangular form (which is what we have), polar form or parametric form.

Rectangular form is an equation using x and y where one variable is defined in terms of the other. We have y in terms of x. For this, we define ds as follows: ds= \sqrt{1+( \frac{dy}{dx})^2 } dx

As a note for a function x in terms of y simply switch each dx in the above to dy and vice versa.

As you can see from the formula we need to find dy/dx and square it. Let's do that now.

We can use the chain rule: bring down the 3/2, keep the parenthesis, raise it to the 3/2 - 1 and then take the derivative of what's inside (here x^2-4). More formally, we can let u=x^{2} -4 and then consider the derivative of u^{3/2}du. Either way, we obtain,

\frac{dy}{dx}=( \frac{1}{6})( x^{2} -4)^{1/2}(2x)=( \frac{x}{2})( x^{2} -4)^{1/2}

Looking at the formula for ds you see that dy/dx is squared so let's square the dy/dx we just found.
( \frac{dy}{dx}^2)=( \frac{x^2}{4})( x^{2} -4)= \frac{x^4-4 x^{2} }{4}

This means that in our case:
ds= \sqrt{1+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{4}{4}+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{x^4-4 x^{2}+4 }{4}} dx
ds= \sqrt{\frac{( x^{2} -2)^2 }{4}} dx
ds=  \frac{x^2-2}{2}dx =( \frac{1}{2} x^{2} -1)dx

Recall, the formula for arc length: L= \int\limits^c_d {ds}
Here, the limits of integration are given by 5 and 9 from the initial problem (the values of x over which we are computing the length of the curve). Putting it all together we have:

L= \int\limits^9_5 { \frac{1}{2} x^{2} -1 } \, dx = (\frac{1}{2}) ( \frac{x^3}{3}) -x evaluated from 9 to 5 (I cannot seem to get the notation here but usually it is a straight line with the 9 up top and the 5 on the bottom -- just like the integral with the 9 and 5 but a straight line instead). This means we plug 9 into the expression and from that subtract what we get when we plug 5 into the expression.

That is, [(\frac{1}{2}) ( \frac{9^3}{3}) -9]-([(\frac{1}{2}) ( \frac{5^3}{3}) -5]=( \frac{9^3}{6}-9)-( \frac{5^3}{6}-5})=\frac{290}{3}


8 0
3 years ago
Math - algebra (9th grade) please include work
Naily [24]

Answer:

Step-by-step explanation:

Y)  \frac{x+4}{8} = 3

*multiply both sides by 8 - cancels out 8 in denominator*

x + 4 = 24

*subtract 4 from both sides*

x = 20

E) \frac{x-5}{2} = 1

*multiply both sides by 2 - cancels out 2 in denominator*

x - 5 = 2

*add 5 on both sides*

x = 7

N) \frac{x+2}{4} = 2

* multiply both sides by 4 - cancels out 4 in denominator*

x + 2 = 8

*subtract 2 from both sides*

x = 6

3 0
2 years ago
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