Answer:
Step-by-step explanation:
Area of rectangle = length * width
= (x + 4) (5x)
= x *5x + 4 *5x
= 5x² + 20x
Perimeter of rectangle = 2*(length + width)
= 2*(x + 4 + 5x)
= 2*(6x + 4)
= 2*6x + 2 *4
= 12x + 8
Okay, here we have this:
Considering the provided function, we are going to calculate the requested one-side limits, so we obtain the following:
Answer:
![\large\boxed{4\sqrt[3]{64}=16}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B4%5Csqrt%5B3%5D%7B64%7D%3D16%7D)
Step-by-step explanation:
![\sqrt[3]{a}=b\iff b^3=a\\\\4\sqrt[3]{64}=(4)(4)=16\\\\\sqrt[3]{64}=4\ \text{because}\ 4^3=64](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Ba%7D%3Db%5Ciff%20b%5E3%3Da%5C%5C%5C%5C4%5Csqrt%5B3%5D%7B64%7D%3D%284%29%284%29%3D16%5C%5C%5C%5C%5Csqrt%5B3%5D%7B64%7D%3D4%5C%20%5Ctext%7Bbecause%7D%5C%204%5E3%3D64)
C < 5
there will be an open circle on 5....it is open because there is no equal sign in the problem.....the shading will be to the left....because less then is shaded to the left
Answer:
1:3
Step-by-step explanation:
3 divide 3 1
9 divide 3 3
