(3x)2(2x)31 x2 1 x cxn, (2x 2) 1 2x2 (2x 2) 1 (2x) 2 2 1x 2 2x2 2 1x 2 (2x)2 2x 2<span>
But
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Answer:
The function f(x) is positive in the interval (-≠,-2.5) ∪ (1,∞)
Step-by-step explanation:
we have

This is a vertical parabola open upward (the leading coefficient is positive)
The vertex is a minimum
The coordinates of the vertex is the point (h,k)
step 1
Find the vertex of the quadratic function
Factor the leading coefficient 2

Complete the square


Rewrite as perfect squares

The vertex is the point (-\frac{3}{4},-\frac{49}{8})
step 2
Find the x-intercepts (values of x when the value of f(x) is equal to zero)
For f(x)=0



take the square root both sides




therefore
The function f(x) is negative in the interval (-2.5,1)
The function f(x) is positive in the interval (-≠,-2.5) ∪ (1,∞)
see the attached figure to better understand the problem
Answer:
x=0
y=3
Step-by-step explanation:
2(x+3)=2x+6, substituting the first equation in the second
2x+6=2x+6, rearranging the equations
2x-2x=6-6
0=0
y=0+3
y=3
Answer:
6 3/16 in²
Step-by-step explanation:
Area of rectangle = width x length
Given:
width = 2 3/4 in
length = 2 1/4 in
⇒ area = 2 3/4 × 2 1/4 = 11/4 × 9/4 = 99/16 = 6 3/16 in²